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Varvara68 [4.7K]
2 years ago
8

What are the best practices while sharing a lab balance with other students? Select one or more: Leave a note when you have tare

d a balance for your glassware. Brush off any chemical dust around the balance after each use. Alert your TA or instructor about any issues with the balance. Place samples directly onto the balance.
Chemistry
1 answer:
ivann1987 [24]2 years ago
7 0

Answer:

  • Brush off any chemical dust around the balance after each use
  • Alert your TA or instructor about any issues with the balance

Explanation:

The best practices while sharing a lab balance with other students includes alerting your TA or instructor about issues with the balance and Brushing off any chemical dust around the balance after each use. the practices will help to avert/reduce the work hazards associated with working with a balance.

Brushing off any chemical dust after each use will reduce the chemical hazards in the lab while Alerting your instructor about any issues with the balance helps to eliminate mechanical hazards that a faulty balance can pose

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vesna_86 [32]

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4 0
2 years ago
Instrumental methods need only a microscopic sample to return an accurate result. Why is this so?
uranmaximum [27]
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3 0
2 years ago
How many atoms is 3.49x1032 moles of KOH?
antoniya [11.8K]
2.10098*10^47 atoms
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7 0
2 years ago
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Freon-12, CF2Cl2, which has been widely used in air conditioning systems, is considered a threat to the ozone layer in the strat
Vilka [71]

Answer:

The root mean squared velocity for CF2Cl2 is  v_{rms}= 207.06 m/s

Explanation:

From the question we are told that

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Root Mean Square velocity is mathematically represented as

      v _{rms} = \sqrt{\frac{3RT}{MW} }

 Where  T is the temperature

              MW is the molecular weight of gas

              R is the gas constant with a value of  R = 8.314 JK^{-1} mol^{-1}

For  CF2Cl2 its molecular weight is  0.121 kg/mol

     Substituting values

  v_{rms} = \sqrt{\frac{3 * 8.314 *208}{0.121} }

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5 0
2 years ago
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zalisa [80]

Answer:

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So, for this case, ΔH=ΔU.

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2 reactant moles*\frac{-184.6kJ}{mol}

ΔU=-369.2 kJ/mol.

4 0
2 years ago
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