we are given
a swimming pool contains 2,850 kiloliters (kL) of water
2,850 kiloliters (kL)=2850000L
we know that


Firstly , we will find for 1L

now, we can multiply both sides by 2850000



so,
a swimming pool contains 752972.25892gal of water...........Answer
Answer:
In order to react with 45 g of water 1.25 moles of CaC₂ are required.
Explanation:
Given data:
Moles of CaC₂ needed = ?
Mass of water = 45.0 g
Solution:
Chemical equation:
CaC₂ + 2H₂O → C₂H₂ + Ca(OH)₂
Number of moles of water:
Number of moles = mass/ molar mass
Number of moles = 45 g/ 18 g/mol
Number of moles = 2.5 mol
Now we will compare the moles of water and CaC₂ from balance chemical equation:
H₂O : CaC₂
2 : 1
2.5 : 1/2×2.5 =1.25 mol
In order to react with 45 g of water 1.25 moles of CaC₂ are required.
Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)
v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol
n(Na₂S)=n{Cd(NO₃)₂}=cv
m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv
m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
Answer:
a chain reaction that is caused by nuclear fusion
Explanation:
basics in math or pre calculus