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PIT_PIT [208]
2 years ago
14

To prepare a 2 M solution of potassium nitrate (KNO3), which quantities must be measured? The mass of the and the volume of the

must be measured.
Chemistry
2 answers:
PtichkaEL [24]2 years ago
7 0

Answer:

Mass of salt and Volume of water

Explanation:

To prepare 2M solution of potassium nitrate. A certain mass of salt has to be weighed and dissolved in measured volume of water.

The 2M signifies the molarity (concentration) of the salt. It is given as;

Molarity =  moles / volume (liter) of solution.

Moles = Mass /  Molar mass

To get a molarity of 2 in a 1L water, our moles needs to be;

2 = moles / 1

moles = 2

substituting into the moles mass equation;

molar mass = 101.1032 g/mol

2 = mass / 101.1032

mass = 2 * 101.1032

mass = 202.2064g

This means 202.2064g of potassium ntrate needs to be dissolved in 1L of water to acheve a molarity of 2.

Olin [163]2 years ago
4 0

Answer:

The mass of the solute and the volume of the solution.

Explanation:

Hello,

In this case, given the formula of molarity:

M=\frac{n_{solute}}{V_{solution}}

In such a way, since the moles could not be directly measured, we must measure the mass of the solute and by using its molar mass, one could compute its moles. Moreover, since the solution is composed by the solvent (typically water) and the solute, we consequently must measure the volume of the solution needed for the preparation of such concentration-known solution. In such a way, we can actually prepare the required solution.

Best regards.

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If a swimming pool contains 2,850 kiloliters (kL) of water, how many gallons (gal) of water does it contain? (1 gal = 3.785 L)
siniylev [52]

we are given

a swimming pool contains 2,850 kiloliters (kL) of water

2,850 kiloliters (kL)=2850000L

we know that

1gal=3.785L

3.785L=1gal

Firstly , we will find for 1L

1L=\frac{1}{3.785}gal

now, we can multiply both sides by 2850000

2850000*1L=2850000*\frac{1}{3.785}gal

2850000L=2850000*\frac{1}{3.785}gal

2850000L=752972.25892gal

so,

a swimming pool contains 752972.25892gal of water...........Answer


6 0
2 years ago
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How many moles of CaC2 are needed to react completely with 45.0g H2O?
sertanlavr [38]

Answer:

In order to react with 45 g of water 1.25 moles of CaC₂ are required.

Explanation:

Given data:

Moles of CaC₂ needed = ?

Mass of water = 45.0 g

Solution:

Chemical equation:

CaC₂ + 2H₂O      →      C₂H₂ + Ca(OH)₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 45 g/ 18 g/mol

Number of moles = 2.5 mol

Now we will compare the moles of water and CaC₂ from balance chemical equation:

                     H₂O             :             CaC₂

                       2                :                1

                     2.5              :             1/2×2.5 =1.25 mol

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6 0
2 years ago
How many milligrams of sodium sulfide are needed to completely react with 25.00 ml of a 0.0100 m aqueous solution of cadmium nit
NARA [144]
Na₂S(aq) + Cd(NO₃)₂(aq) = CdS(s) + 2NaNO₃(aq)

v=25.00 mL
c=0.0100 mmol/mL
M(Na₂S)=78.046 mg/mmol

n(Na₂S)=n{Cd(NO₃)₂}=cv

m(Na₂S)=M(Na₂S)n(Na₂S)=M(Na₂S)cv

m(Na₂S)=78.046*0.0100*25.00≈19.5 mg
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2 years ago
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Which type of reaction does this diagram represent?
Leviafan [203]

Answer:

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Explanation:

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