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lorasvet [3.4K]
2 years ago
11

Suppose that a 100 mL sample of ideal gas is held in a piston-cylinder apparatus. Its volume could be increased to 200 mL by

Chemistry
1 answer:
Ivahew [28]2 years ago
6 0

Answer:

e. reducing the pressure from 608 torr to 0.40 atm at constant temperature.

Explanation:

According to Boyle's law when a gas is at the same temperature and there is a mass in a closed container so the pressure and the volume changes in the opposite direction

So here the equation is

P_1V_1=P_2V_2

Now we choose the options

where,

V_1 =  100\ mL = 0.1\ L\\\\V_2 =  200\ mL = 0.2\ L

P_1 = 608\ torr = 0.8\ atm \\\\P_2= 0.4\ atm

Now applying these values to the above equation

So,

P1V1=P2V2

P_1V_1=P_2V_2

0.8\times0.1 = 0.4\times0.2

0.8 = 0.8

Hence, it is proved

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(a) The mass density of a gaseous compound was found to be 1.23 kg m^−3 at 330 K and 20 kPa. What is the molar mass of the compo
Luden [163]

Answer:

The molar mass of the compound is:- 168.82 g/mol

The molar mass of the gas is:- 16.38 g/mol

Explanation:

(a)

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Also,  

Moles = mass (m) / Molar mass (M)

Density (d)  = Mass (m) / Volume (V)

So, the ideal gas equation can be written as:

PM=dRt

Given that:-

Pressure = 20 kPa = 20000 Pa

The expression for the conversion of pressure in Pascal to pressure in atm is shown below:

P (Pa) = \frac {1}{101325} P (atm)

20000 Pa = \frac {20000}{101325} atm

Pressure = 0.1974 atm

Temperature = 330 K

d = 1.23 kg/m³ = 1.23 g/L

Molar mass = ?

Applying the equation as:

0.1974 atm × M = 1.23 g/L × 0.0821 L.atm/K.mol × 330 K

⇒M = 168.82 g/mol

<u>The molar mass of the compound is:- 168.82 g/mol</u>

(b)

Given that:

Pressure = 152 Torr

Temperature = 298 K

Volume = 250 cm³ = 0.25 L

Using ideal gas equation as:

PV=nRT

R = 62.3637\text{torr}mol^{-1}K^{-1}

Applying the equation as:

152 Torr × 0.25 L = n × 62.3637 L.torr/K.mol × 298 K

⇒n = 0.002045 moles

Given that :  

Mass of the gas = 33.5 mg = 0.0335 g

Molar mass = ?

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.002045\ moles&#10;= \frac{0.0335\ g}{Molar\ mass}

<u>The molar mass of the gas is:- 16.38 g/mol</u>

5 0
2 years ago
What is the empirical formula? A compound is used to treat iron deficiency in people. It contains 36.76% iron, 21.11% sulfur, an
Mandarinka [93]

Answer: The empirical formula of the compound is Fe_1S_1O_4

Explanation:

Empirical formula is defined formula which is simplest integer ratio of number of atoms of different elements present in the compound.

Percentage of iron in a compound = 36.76 %

Percentage of sulfur in a compound = 21.11 %

Percentage of oxygen in a compound = 42.13 %

Consider in 100 g of the compound:

Mass of iron in 100 g of compound = 36.76 g

Mass of iron in 100 g of compound = 21.11 g

Mass of iron in 100 g of compound = 42.13 g

Now calculate the number of moles each element:

Moles of iron=\frac{36.76 g}{55.84 g/mol}=0.658 mol

Moles of sulfur=\frac{21.11 g}{32.06 g/mol}=0.658 mol

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Divide the moles of each element by the smallest number of moles to calculated the ratio of the elements to each other

For Iron element = \frac{0.658 mol}{0.658 mol}=1

For sulfur element = \frac{0.658 mol}{0.658 mol}=1

For oxygen element = \frac{2.633 mol}{0.658 mol}=4.001\approx 4

So, the empirical formula of the compound is Fe_1S_1O_4

4 0
2 years ago
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An increase in temperature will effect vapor pressure by:
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Answer: Increases.

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What is the maximum number of hydrogen atoms that can be covalently bonded in a molecule containing two carbon atoms?a) 2b) 3c)
aksik [14]

Answer:

           The correct answer is Option-D (6 Hydrogen atoms).

Explanation:

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                  As carbon has four valence electrons so, it has the ability to make four single bonds. In given molecule each carbon has already made a single bond with another carbon therefore, each carbon is left with three more unpaired electrons which will make covalent bond with three hydrogen atoms each as shown in attached structure.

8 0
2 years ago
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