Question

Suppose that a 100 mL sample of ideal gas is held in a piston-cylinder apparatus. Its volume could be increased to 200 mL by

Answer 1

Answer:

e. reducing the pressure from 608 torr to 0.40 atm at constant temperature.

Explanation:

According to Boyle's law when a gas is at the same temperature and there is a mass in a closed container so the pressure and the volume changes in the opposite direction

So here the equation is

$P_1V_1=P_2V_2$

Now we choose the options

where,

$V_1 = 100\ mL = 0.1\ L\\\\V_2 = 200\ mL = 0.2\ L$

$P_1 = 608\ torr = 0.8\ atm \\\\P_2= 0.4\ atm$

Now applying these values to the above equation

So,

P1V1=P2V2

$P_1V_1=P_2V_2$

$0.8\times0.1 = 0.4\times0.2$

0.8 = 0.8

Hence, it is proved