Formula of hydrated sodium carbonate : Na₂CO₃.10H₂O, so moles of water in one mole of hydrated salt = 10
<h3>Further explanation</h3>
Hydrate is a compound that binds water (H₂O), usually in the form of crystals/ solids
If these compounds are dissolved in water or heated, the hydrates can decompose:
Example: X.YH₂O (s) → X (aq) + YH₂O (l)
The formula for the hydrated compound contains: YH2O
The mole ratio shows the ratio of the coefficients of the hydrate compound
10.45 hydrated sodium carbonate(Na₂CO₃.xH₂O) were heated until 3.87 of 3.87of anhydrous (Na₂CO₃) remained, so
mass H₂O released :
mass Na₂CO₃ = 3.87 g
mol ratio Na₂CO₃(MW= g/mol) : H₂O(MW=18 g/mol) =
Molarity = number of mole of substance(n) / volume of solution (V).
n(CaCl2) = mass (CaCl2)/M(CaCl2)
M(CaCl2) = 40+2*35.5 = 111 g/mol
n(CaCl2) =39.5 g CaCl2*1 mol/111g
0.250 M = 39.5 g CaCl2*1 mol/111g*volume of solution (V).
volume of solution (V) = 39.5 g CaCl2*1 mol/(0.250 M*111g) = 1.42 L
Answer:
2
Explanation:
Isomers are molecules with the same molecular formula, but with some difference. If that difference is in the manner the atoms are distributed in the molecule, they are called structural isomers; if the difference is the way the molecule is in space, they're called space isomers (cis/trans); and there are the stereoisomers, which the molecules are images that can be overlapping.
The stereoisomers have the property to deviate the polarized light, and, when a molecule has a chiral carbon, it means that it has stereoisomers. The number of stereoisomers is 2ⁿ, where n is the number of chiral carbons.
Chiral carbon is a carbon that bonds with four different structures. So, below is represented the molecule of propylene glycol, and it has only one chiral carbon (see the blue arrow), so, it has only 2 stereoisomers.
Answer:6.719Litres of Cl2 gas.
Explanation:According to eqn of rxn
2Na +Cl2=2NaCl
P=689torr=689/760=0.91atm
T=39°C+273=312K
according to stoichiometry of the reaction,1Moles of Cl2 gives 2moles of NaCl
But 28g of NaCl was given,we have to convert this to moles by using the relation, n=mass/MW
MW of NaCl=23+35.5=58.5g/mol
n=28g(mass given of NaCl)/58.5
n=0.479moles of NaCl
Going back to the reaction,
if 1moles of Cl2 produces 2moles of NaCl
x moles of Cl2 will give 0.479moles of NaCl.
x=0.479*1/2
x=0.239moles of Cl2.
To find the volume, we use ideal ggas eqn,PV=nRT
V=nRT/P
V=0.239*0.082*312/0.91
V=6.719Litres
A 0.200 M of K2SO4 solution is produced by diluting 20.0 mL of 5.00 M K2SO4 solution to 500.0 mL.
<u>Explanation</u>:
- When dealing with dilution we will use the following equation:
M1 V1 = M2 V2
where,
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
- By diluting 20.0 mL of 5.00 M K2SO4 solution to 500.0 mL, we get
M1 V1 = M2 V2
20.0 mL 
5.00 M = M2 500.0 mL
M2 = (20.0 mL 5.00 M) / 500.0 mL
M2 = 0.200 M.
Hence A 0.200 M of K2SO4 solution is produced by diluting 20.0 mL of 5.00 M K2SO4 solution to 500.0 mL.
