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S_A_V [24]
2 years ago
14

Consider the acid H3PO4. This acid will react with water by the following equation. H3PO4+H2O↽−−⇀H2PO−4+H3O+ What will be true o

f the resulting conjugate base H2PO−4? Select the correct answer below: H2PO−4 can act as an acid.
Chemistry
1 answer:
Sonbull [250]2 years ago
7 0

Answer:

H+/PO-4^-2

Explanation:

hydrogen has dissolved completely

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What molecule is the ultimate source of hydrogen ions that are secreted into the gastric juice?
sladkih [1.3K]

Answer: carbonic acid

Explanation:

8 0
2 years ago
Octane (C8H18) undergoes combustion according to the following thermochemical equation. 2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(l
Zepler [3.9K]

Answer: The standard enthalpy of formation of liquid octane is -250.2 kJ/mol

Explanation:

The given balanced chemical reaction is,

2C_8H_{18}(l)+25O_2(g)\rightarrow 16CO_2(g)+18H_2O(l)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{O_2}\times \Delta H_f^0_{(O_2)}+n_{H_2O}\times \Delta H_f^0_{(H_2O)}]-[n_{C_8H_{18}}\times \Delta H_f^0_{(C_8H_{18})+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

We are given:

\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(C_8H_{18}(l))}=?kJ/mol\\\Delta H^o_f_{(H_2O(l))}=-285.8kJ/mol

Putting values in above equation, we get:

-1.0940\times 10^4=[(16\times -393.5)+(18\times -285.8)]-[(25\times 0)+(2\times \Delat H_f{C_8H_{18}(l)}]

\Delta H^o_f_{(C_8H_{18}(l))}=-250.2kJ/mol

Thus the standard enthalpy of formation of liquid octane is -250.2 kJ/mol

4 0
2 years ago
The lewis structure of n2h2 shows __________.
Ghella [55]
The Lewis structure of Diimide (N₂H₂) is shown below.

In this molecule two Nitrogen atoms attached to each other through a double bond are further attached to one one Hydrogen atom. Also, each Nitrogen atom carries one non-binding electron pair (Lone Pair) (Highlighted RED).

Result:
          Option-C (<span>each nitrogen has one nonbinding electron pair) is the correct answer.</span>

5 0
2 years ago
Read 2 more answers
Calculate the number of grams of solute in 500.0 mL of 0.189 M KOH.
KIM [24]

Answer : The number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

Solution : Given,

Volume of solution = 500 ml

Molarity of KOH solution = 0.189 M

Molar mass of KOH = 56 g/mole

Formula used :

Molarity=\frac{\text{Mass of KOH}\times 1000}{\text{Molar mass of KOH}\times \text{Volume of solution in ml}}

Now put all the given values in this formula, we get the mass of solute KOH.

0.189M=\frac{\text{Mass of KOH}\times 1000}{(56g/mole)\times (500ml)}

\text{Mass of KOH}=5.292g

Therefore, the number of grams of solute in 500.0 mL of 0.189 M KOH is, 5.292 grams

7 0
2 years ago
Read 2 more answers
If Mary drove 525miles in 7hours at an average speed of 75 miles per hour how much faster would her average speed need to be to
Makovka662 [10]
<h3>Answer:</h3>

30 miles per hour faster

<h3>Explanation:</h3>

We are given;

  • Distance that Mary drove as 525 miles
  • Time she took as 7 hours
  • Average speed as 75 miles per hour

We are supposed to determine how fast the average speed would be if she made the trip in 5 hours.

  • We know that speed is given by dividing distance by time taken.
  • In this case distance remained constant

Therefore, we can determine the speed when she took 5 hours

  • Speed = Distance ÷ time

           = 525 miles ÷ 5 hours

           = 105 hours

Thus, the new speed would be 105 miles per hours

But, initial speed was 75 miles per hour

Therefore, she would travel 30 miles per hour faster to cover the journey in 5 hours.

6 0
2 years ago
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