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leva [86]
2 years ago
14

In a coffee shop, the following coffee samples are prepared for customers. i. 10 g of sugar added to 100 g of coffee ii. 10 g of

sugar added to 200 g of coffee iii. 4 g of sugar added to 200 g of coffee iv. 4 g of sugar added to 100 g of coffee Based on the amount of sugar added, which sequence ranks the coffee from the sweetest coffee to the least-sweet coffee?
Chemistry
2 answers:
madreJ [45]2 years ago
8 0

The answer is:   i, ii, iv, iii

dem82 [27]2 years ago
4 0

So solve this we must know the amount of sugar per gram of coffee

<span>i.              </span>10 g sugar /100 g coffee = 0.1 g sugar/ 1 g coffee

<span>ii.            </span>10 g sugar / 200 g coffee = 0.05 g sugar / 1 g coffee

<span>iii.           </span>4 g sugar / 200 g coffee = 0.02 g sugar / 1 g coffee

<span>iv.           </span>4 g sugar / 100 g coffee = 0.04 g sugar / 1 g coffee

 

So the ranking from sweetest so the least is:

<span> i, ii, iv, iii</span>

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Answer:

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Across:

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4 0
1 year ago
a mixture was found to contain 1.05g of sio2, 0.69g of cellulose, and 1.82g of calcium carbonate, what percentage of calcium car
enot [183]
Mass percentage is another way of expressing concentration of a substance in a mixture. Mass percentage is calculated as the mass of a component divided by the total mass of the mixture, multiplied by 100%. It is calculated as follows:

% CaCO3 = (<span>1.82g of calcium carbonate</span> / (1.05 g SiO2 + 0.69 g of cellulose + <span>1.82g of calcium carbonate)) x 100% = 51.12% Calcium carbonate</span>
6 0
1 year ago
Find the molarity of 750 ml solution containing 346 g of potassium nitrate
Zinaida [17]
Given mass of KNO₃=346g
Molar mass of KNO₃=(39.098)+(14)+(15.99*3)=101.068gmol⁻¹
Volume of Solution=750ml=0.75dm³

Molarity=(mass of solute/molar mass of solute)*(1/volume of sol. in dm³)
            =(346/101.068)*(1/0.75)
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5 0
2 years ago
Which statement best compares the energy involved in melting with the energy involved in boiling for a given liquid?
Soloha48 [4]
C its c trust me i just took the quiz
4 0
2 years ago
Read 2 more answers
Consider the reaction H2(g) + Cl2(g) → 2HCl(g)ΔH = −184.6 kJ / mol If 2.00 moles of H2 react with 2.00 moles of Cl2 to form HCl,
zalisa [80]

Answer:

ΔU=-369.2 kJ/mol.

Explanation:

We start from the equation:

Δ(H)=ΔU+Δ(PV), which is an extension of the well known relation: H=U+PV.

If Δ(PV) were calculated by ideal gas law,

PV=nRT

Δ(PV)=RTΔn.

Where Δn is the change of moles due to the reaction; but, this reaction does not give a moles change (Four moles of HCl produced from 4 moles of reactants), so Δ(PV)=0.

So, for this case, ΔH=ΔU.

The enthalpy of reaction given is for one mole of reactant, so the enthalpy of reaction for the reaction of interest must be multiplied by two:

2 reactant moles*\frac{-184.6kJ}{mol}

ΔU=-369.2 kJ/mol.

4 0
2 years ago
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