Question

A chamber with a fixed volume is shown above. The temperature of the gas inside the chamber before heating is 25.2 C and it’s pressure is 0.600 atm. The gas is heated with a flame to a temperature of 72.4 C, what is it’s pressure at this temperature

Answer 1

Answer:

Explanation:

Given parameters:

Initial temperature T₁  = 25.2°C  = 25.2 + 273  = 298.2K

Initial pressure  = P₁  = 0.6atm

Final temperature = 72.4°C   = 72.4 + 273  = 345.4K

Unknown:

Final pressure = ?

Solution:

To solve this problem, we use an adaption of the combined gas law where the volume gas is fixed. This simplification results into:

                  $\frac{P_{1} }{T_{1} } = \frac{P_{2} }{T_{2} }$

where P and T are temperatures, 1 and 2 are initial and final temperatures.

 Input the parameters and solve;

          $\frac{0.6}{298.2} = \frac{P_{2} }{345.4}$  

          P₂   = 0.7atm