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expeople1 [14]
2 years ago
8

Complete the sentences to explain why the molecule ch3f is polar.

Chemistry
2 answers:
Lelu [443]2 years ago
8 0
A group of environmentalists were discussing the benefits and drawbacks associated with using fossil fuels. Which argument <span>best </span>fits the conversation? 
Fossil fuels are cheaper than alternative forms of energy.Fossil fuel reserves will never be depleted.<span>Fossil fuels are easily renewed. </span><span>Fossil fuel use does not affect the environment.</span>
Charra [1.4K]2 years ago
7 0

Answer:

Yes CH_3F is polar.

Explanation:

We know in polar molecules the Vector sum of all the individual bond dipole is non zero.

We know CH_3F is a sp_3 hybridized molecule. Therefore, its configuration is tetrahedral with 3 C-H bonds and on C-F

bond .

Since fluorine is much electronegative than hydrogen. Therefore, dipole moment of C-F bond is more than dipole moment of C-H

bond.

Therefore, vector addition of all the bonds in sp_3 hybridization is non zero due to which CH_3F is polar.

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A sample of H2SO4 contains 2.02 g of hydrogen, 32.07 g of sulfur, and 64.00 g of oxygen. How many grams of sulfur and grams of o
Gemiola [76]
From the chemical formula of sulfuric acid, we can see the molar ratio:

H : S : O 
2 : 1 : 4

Now, we convert the mass of hydrogen given into the moles of hydrogen. This is done using

Moles = mass / Mr
Moles = 7.27 / 1
Moles = 7.27

Therefore, the moles will be:

S = 7.27 / 2 = 3.64 moles
O = 7.27 * 2 = 14.54 moles

Now, the respective masses are:
S = 32 * 3.64 = 116.48 grams
O = 16 * 14.54 = 232.64 grams 
7 0
2 years ago
Calculate the molarity of sodium chloride in a half-normal saline solution (0.45% NaCl). The molar mass of NaCl is
Rus_ich [418]

Answer:

0.077 M

Explanation:

Data Given :

The concentration of half normal (NaCl) saline = 0.45g / 100 g

So,

Volume of Solution = 100 g = 100 mL

Volume of Solution in Liter = 100 mL / 1000

Volume of Solution = 0.1 L

molar mass of NaCl = 58.44 g/mol

Molarity:

Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M

Formula used for Molarity

                M = moles of solute / Liter of solution . . . . . . . . . . (1)

Now to find number of moles of Nacl

                no. of moles of NaCl = mass of NaCl / molar mass

                no. of moles of NaCl = 0.45g / 58.44 g/mol

               no. of moles of NaCl = 0.0077 g

Put values in the eq (1)

                  M = moles of solute / Liter of solution . . . . . . . . . . (1)

                  M = 0.0077 g / 0.1 L

                  M = 0.077 M

So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M

3 0
2 years ago
What mass of solid lead would displace exactly 234.6 liters of water?
eimsori [14]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

The mass of solid lead would displace exactly 234.6 liters of water should be <span>2,674,440</span>
6 0
2 years ago
Read 2 more answers
A gas occupies 72.1 at stp. At what temperature would the gas occupy 85.9 L at a pressure of 93.6 kPa?
Alika [10]

Answer:

328.1 K.

Explanation:

  • To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT</em>.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in.

  • If n is constant, and have two different values of (P, V and T):

<em>P₁V₁T₂ = P₂V₂T₁</em>

<em></em>

P₁ = 1.0 atm (standard P), V₁ = 72.1 L, T₁ = 25°C + 273 = 298 K (standard T).

P₂ = 93.6 kPa = 0.924 atm, V₂ = 85.9 L, T₂ = ??? K.

<em>T₂ = P₂V₂T₁/P₁V₁ = </em>(0.924 atm)(85.9 L)(298 K)/(1.0 atm)(72.1 L) <em>= 328.1 K.</em>

<em></em>

4 0
2 years ago
1. Draw the basic repeating unit of sodium alginate polymer. 2. What is this polymer used for?
tamaranim1 [39]

Answer:

1.The diagram is attached

2.sodium alginate is a polymer which can be extracted from brown seaweed and is used for defloculating, gelling and thickening

Used also in dermatological preparation

Used in adhensive paste

8 0
2 years ago
Read 2 more answers
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