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Ratling [72]
2 years ago
14

How many moles are in 19.6 g of Sodium (Na)? And the conversion factor?

Chemistry
1 answer:
Snezhnost [94]2 years ago
6 0

Answer:

n=0.852 moles

Explanation:

Given mass is, m = 19.6 g

The molar mass of sodium is, M = 22.99 u

We need to find the no of moles in 19.6 of Sodium. We know that, no of moles is equal to given mass divided by molar mass.

n=\dfrac{m}{M}\\\\n=\dfrac{19.6}{22.99}\\\\n=0.852

So, there are 0.852 moles in 19.6 g of Sodium.

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6. Un volumen de 1.0 mL de agua de mar contiene casi 4 x 10-12 g de Au. El volumen total de agua en los océanos es de 1.5 x 1021
Aleks [24]

Answer:

The total amount of Au is $ 2.0\times10^{24}

Explanation:

Given that,

Mass of 1.0 ml of Au m=4\times10^{-2}\ g

Total volume of water in oceans V=1.5\times10^{21}\ L

We need to calculate the volume in ml

Using given volume

V=1.5\times10^{21}\times1000\ mL

V=1.5\times10^{24}\ mL

We need to calculate the total mass of Au  

Using given data

1\ ml\ volume = 4\times10^{-2}\ g

1.5\times10^{24}\ ml=4\times10^{-2}\times1.5\times10^{24}

So, The total mass of Au is 6\times10^{22}\ g

The mass will be in ounce,

Mass=0.035274\times6\times10^{22}

Mass=2.12\times10^{21}\ ounce

The total amount of the Au Will be

Total\ amount=2.12\times10^{21}\times948

Total\ amount=2.0\times10^{24}

Hence, The total amount of Au is $ 2.0\times10^{24}

3 0
1 year ago
Draw a sodium formate molecule. The structure has been supplied here for you to copy. To add formal charges, click the button be
Karo-lina-s [1.5K]

The Molecule of Sodium Formate along with Formal Charges (in blue) and lone pair electrons (in red) is attached below.

Sodium Formate is an ionic compound made up of a positive part (Sodium Ion) and a polyatomic anion (Formate).

Nomenclature:

                       In ionic compounds the positive part is named first. As sodium ion is the positive part hence, it is named first followed by the negative part i.e. formate.

Name of Formate:

                             Formate ion has been derived from formic acid ( the simplest carboxylic acid). When carboxylic acids looses the acidic proton of -COOH, they are converted into Carboxylate ions.

E.g.

                    HCOOH (formic acid)    →     HCOO⁻ (formate)  +  H⁺

                H₃CCOOH (acetic acid)     →      H₃CCOO⁻ (acetate)  +  H⁺

Formal Charges:

                           Formal charges are calculated using following formula,

          F.C  =  [# of Valence e⁻] - [e⁻ in lone pairs + 1/2 # of bonding electrons]

For Oxygen:

                    F.C  =  [6] - [6 + 2/2]

                    F.C  =  [6] - [6 + 1]

                    F.C  =  6 - 7

                    F.C  =  -1

For Sodium:

                    F.C  =  [1] - [0 + 0/2]

                    F.C  =  [1] - [0]

                    F.C  =  1 - 0

                    F.C  =  +1

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2 years ago
Draw the product(s) obtained when benzoquinone is treated with excess butadiene. using wedges and dashes, indicate the stereoche
Alex17521 [72]

Answer:

The structure can be found on the attached documents

Explanation:

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1 year ago
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Ira Lisetskai [31]

Answer:

2 I Think

Explanation:

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Imagine you are a detective examining a crime scene. You are trying to
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Answer:

C. pieces of hair found at the crime scene.

Explanation:

using the pieces of hair, you can get the DNA of the person. This will give u a better lead in solving the crime.

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