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miskamm [114]
2 years ago
14

Jane Doe has a cholesterol (C27H46O) count of 178 mg/dL. How many cholesterol molecules does Jane Doe have in each deciliter of

blood?
Chemistry
1 answer:
Ilya [14]2 years ago
4 0

Answer:

Jane has 2.77 * 10^20 molecules cholesterol in 1 dL of blood

Explanation:

<u>Step 1:</u> Given data

Molar mass of Cholesterol =  386.654 g/mol

Jane has a cholesterol of 178 mg/dL

<u>Step 2:</u> Calculate mass of cholsterol in 1 dL

178 mg/dL means in 1 dL she has 178 mg cholesterol or 0.178 grams

<u>Step 3</u>: Calculate number of moles of cholesterol

Number of moles = mass of cholesterol / molar mass of cholesterol

Number of moles = 0.178 grams / 386.654 g/mol = 4.6 * 10^-4 moles

<u>Step 4: </u>Calculate number of molecules

Number of molecules = 4.6 * 10^-4 mol * 6.022 *10^23 / mol = 2.77 * 10^20 molecules

Jane has 2.77 * 10^20 molecules cholesterol in 1 dL of blood

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as it has 17000 joules and 1 calorie has 4184 joules, this yogurt serving has 4.06 calories

6 0
1 year ago
Samantha is using a lever to lift a rock. To life the rock most easily, where should she apply force to the lever
Inessa [10]

Answer:

On the opposite side of the rock.

Explanation:

6 0
2 years ago
A sample of neon gas at a pressure of 1.08 atm fills a flask with a volume of 250 mL at a temperature of 24.0 °C. If the gas is
musickatia [10]

Answer:

124.91mL

Explanation:

Given parameters:

P₁  = 1.08atm

V₁  = 250mL

T₁  = 24°C

P₂  = 2.25atm

T₂  = 37.2°C

V₂  = ?

Solution:

To solve this problem, we are going to apply the combined gas law;

              \frac{P_{1} V_{1} }{T_{1} }   =  \frac{P_{2} V_{2} }{T_{2} }

P, V and T represents pressure, volume and temperature

1 and 2 delineates initial and final states

Convert the temperature to kelvin;

        T₁  = 24°C,  T₁   = 24 + 273 = 297K

        T₂  = 37.2°C , T₂  = 37.2 + 273  = 310.2K

Input the variables and solve for V₂

        \frac{1.08 x 250}{298} = \frac{2.25 x V_{2} }{310.2}

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6 0
2 years ago
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

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Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
2 years ago
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Looking at this equation P= (pa*pb)/ (pa+(pb-pa)) ya  where pa=vap press a and ya= vap composition a and P= total pressure,it relates vapor pressure mixture to vapor composition. This is derived using the combination of Dalton's and Raoult's laws.
4 0
2 years ago
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