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RUDIKE [14]
2 years ago
9

Analysis of the water content of a lake found in the desert showed that it contained 16.6 percent chloride ion, and had a densit

y of 1.23 g/mL. What is the molarity of the chloride ion in the water
Chemistry
1 answer:
IRISSAK [1]2 years ago
8 0

Answer : The molarity of the chloride ion in the water is, 5.75 M

Explanation :

As we are given that 16.6 % chloride ion that means 16.6 grams of chloride ion present 100 grams of solution.

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}

\text{Volume of solution}=\frac{100g}{1.23g/mL}=81.3mL

Now we have to calculate the molarity of chloride ion.

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of chloride ion}\times 1000}{\text{Molar mass of chloride ion}\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{16.6g\times 1000}{35.5g/mole\times 81.3mL}=5.75mole/L=5.75M

Thus, the molarity of the chloride ion in the water is, 5.75 M

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A gas occupies 22.4 l at stp and 14.5 l at 100c and 2.00 atm pressure. how many moles of gas did the system gain or lose?
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<span>At standard temperature and pressure 22.4 l of an ideal gas would contain 1 mole. in order to find the change in moles we must look at the ideal gas law PV=nRT where P=Pressure V=volume n=Moles R= Gas constant T= Temperature. To simplify this equation we will be using the gas constant at .08206 L-atm/mol-K. We must first convert 100c to k which is 373.15. Then we can plug the values into our equation which gives us (2atm)(14.5 l)=(n)(.08206 L-atm/mol-K)(373.15). After some basic algebra we get the moles to equal roughly .95 which is .05 moles less than our original system.</span>
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PLEASE HELP!!! The image represents the reaction between a certain number of molecules of N2 and H2.
77julia77 [94]

Answer:

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Explanation:

As per your description:

<u>1. Square on the left: N₂(g)</u>

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<u>2. Square on the right: H₂(g)</u>

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If the maximum possible amount of NH₃ is formed during the reaction, you assume that the reaction goes to completion.

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Since, the squares show that there are 3 molecules of each reactant, the 3 molecules of hydrogen gas will be able to react with 1 molecule of nitrogen gas. When that happens, all the hydrogen gas is consumend and yet two molecules of nitrogen gas will remain unreacted. Hence, the nitrogen gas is the leftover reactant.

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Explanation:

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3                                  R--NH₂                                         Amines

4                                  R--O--R                                         Ethers

5                                   R--CO--R                                      Ketones

6                                   R--CO--H                                     Aldehydes

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8                                   R--CO--X                                     Acid Halides

10                                R--CO--NR₂                                 Acid Amides

11                                 R--CO-OR'                                  Esters

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If one has a solution of 0.10 m silver nitrate and it is diluted by a factor of two, what is the new concentration
Angelina_Jolie [31]
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