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jenyasd209 [6]
1 year ago
15

To help farmers and gardeners, commercial fertilizers have a big three-number "NPK" label on the bag that gives the amounts of t

hree key plant nutrients: nitrogen, phosphorus and potassium. For example, a bag of fertilizer has by mass nitrogen, by mass potassium as potash , and by mass phosphorus as phosphate . Suppose a certain fertilizer has the following composition: ingredient percent by mass ammonium phosphate calcium nitrate urea inert ingredients What should the first (nitrogen) number on the bag label be? That is, calculate the percent by mass of nitrogen in this fertilizer. Round your answer to the nearest percent.

Chemistry
1 answer:
Ludmilka [50]1 year ago
8 0

Answer:

The number on the lag label should be 15.

Explanation:

It seems your question is incomplete, as it is lacking the working values. An internet search showed me the full question, you can see it in the attached picture.

Let's say we have 100 g of the fertilizer.

  • <em>45 g are of ammonium phosphate</em> ( (NH₄)₃PO₄ ), of which:
  • 45 g (NH₄)₃PO₄ * \frac{42 g N}{149g(NH_{4})_{3}PO_{4}} = 12.7 g are of Nitrogen.

(We used the molar mass of ammonium phosphate in the denominator and three times the molar mass of nitrogen in the numerator)

  • <em>18 g are of calcium nitrate</em> (Ca(NO₃)₂), of which:
  • 16 g Ca(NO₃)₂ *\frac{28gN}{164gCa(NO_{3})_{2}} = 2.73 g are of Nitrogen.

So in total there are (12.7+2.73) 15.43 g of Nitrogen in 100 g of the fertilizer. So the percent by mass of nitrogen is 15.43%.

Rounding to the nearest percent the answer is 15.

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When 64.0 g of methanol (CHOH) is burned, 1454 kJ of energy is produced. What is the heat of combustion for methanol?
andreev551 [17]

 The heat  of combustion  for  methanol   is 727  kj/mol


    <em><u>calculation</u></em>

 calculate the moles  of methanol (CH3OH)

moles = mass/molar  mass

molar mass of methanol =  12 +( 1 x3)  +16 + 1= 32 g /mol

moles is therefore= 64.0 g / 32 g/mol =  2 moles


Heat of combustion  is therefore = 1454 Kj / 2 moles =  727  Kj/mol

6 0
1 year ago
A sample of a compound of Cl and O reacts with an excess of H2 to give 0.233g of HCl and 0.403g of H2O. Determine the empirical
Vsevolod [243]

Answer:

Cl₂O₇

Explanation:

For the reaction:

ClₓOₙ + H₂ → HCl + H₂O

Moles of HCl and moles of H₂O are:

HCl: 0.233g HCl ₓ (1mol / 36.46g) = 6.39x10⁻³ mol HCl

H₂O: 0.403g H₂O ₓ (1mol / 18.02g) = 2.236x10⁻² mol H₂O

As you can see, moles of HCl are equivalent to moles of Cl in the compound and moles of H₂O are equivalent to moles of O in the compound, that means:

6.39x10⁻³ mol Cl

2.236x10⁻² mol O

Empirical formula is the simplest ratio of atoms presents in a molecule. If Cl is <em>1</em>, Oxygen will be:

2.236x10⁻² mol / 6.39x10⁻³ = <em>3.5</em>

As empirical formula must be given in natural numbers, the empirical formula is:

<em>Cl₂O₇</em>

<em></em>

4 0
2 years ago
Read 2 more answers
How many miles of Fe2+ ions and MnO4- ions were titrated in each part 1 trial
Fudgin [204]

Answer:

In 1000 ml there is 0.10 moles of Fe 2+

Therefore, in 10 ml there is (0.1/1000)*10= 0.001 mol of Fe2+

mole ratio for rxn Fe2+ : MnO4- is

1 : 2

therefore if 0.001 moles of Fe2+ react then 0.001*2 =0.002 moles of MnO4- react with Fe2+

hence, molarity of MnO4- = (mol*vol)/1000

= 0.002*10.75/1000= 2.15*10-5M

Explanation:

Hope this helps

5 0
2 years ago
You are asked to determine the mass of a piece of copper using its reported density, 8.96 g/ml, and a 150-ml graduated cylinder.
kakasveta [241]

Answer:- Mass of copper piece is 290 gram.

Solution:- We know that, mass = density * volume

density of copper is given as 8.96 gram per mL.

Volume of copper piece is the rise change in volume.

Volume of copper piece = 137 mL - 105 mL = 32 mL

Let's multiply the volume by density to calculate the mass of copper:

mass of copper = 32mL(\frac{8.96g}{mL})

mass of copper = 286.72 g

Volume has two significant figures, so if we round the mass to two significant figures then it becomes 290 g.

7 0
2 years ago
Read 2 more answers
What is the density of 96 ml of a liquid that has a mass of 90.5 g?
Otrada [13]

Answer:

Density = Mass / Volume.   so,  x = 90.5 g / 96 mL ... The Density would be 0.942 g/mL

8 0
2 years ago
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