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2 years ago

How many liters of cane juice is needed to supply 5g sucrose if cane juice contains 12% sucrose

Chemistry

1 answer:

pickupchik [31]2 years ago

6 0

Given parameters:

Mass of sucrose = 5g

Density of sucrose = 1.12g/mL

Percentage of sucrose per liter of cane juice = 12%

Unknown:

Volume of cane juice needed = ?

We need to establish the volume - density relationship. Density is the mass of a substance per unit volume.

Mathematically;

Density = $\frac{mass}{volume}$

Now solve for the volume of sucrose;

1.12g/mL = $\frac{5}{Volume}$

Volume = $\frac{5}{1.12}$ = 4.46mL = 4.46 x 10⁻³L since 1000mL = 1L

Since 12% of 1 liter of cane juice is sucrose;

12% of x liter of cane juice = 4.46 x 10⁻³L

Volume of cane juice = 4.46 x 10⁻³ x $\frac{100}{12}$ = 0.037L

Volume of cane juice is 0.037L

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The pressure of a 609.64 gram sample of F2 in a 88.84 L container is measured to be 2770.96 torr. What is the temperature of thi

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Answer : The temperature of the gas is, 245.9 K

Explanation :

To calculate the temperature of gas we are using ideal gas equation:

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Conversion used : (1 atm = 760 torr)

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Now put all the given values in the ideal gas equation, we get:

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Len [333]

Answer:

The pH of 0.1 M BH⁺ClO₄⁻ solution is 5.44

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Given: The base dissociation constant: $K_{b}$ = 1 × 10⁻⁴, Concentration of salt: BH⁺ClO₄⁻ = 0.1 M

Also, water dissociation constant: $K_{w}$ = 1 × 10⁻¹⁴

The acid dissociation constant ( $K_{a}$ ) for the weak acid (BH⁺) can be calculated by the equation:

$K_{a}. K_{b} = K_{w}$

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Reaction involved: BH⁺ + H₂O ⇌ B + H₃O+

Initial: 0.1 M x x

Change: -x +x +x

Equilibrium: 0.1 - x x x

The acid dissociation constant: $K_{a} = \frac{\left [B \right ] \left [H_{3}O^{+}\right ]}{\left [BH^{+} \right ]} = \frac{(x)(x)}{(0.1 - x)} = \frac{x^{2}}{0.1 - x}$