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1 year ago

6. What is the molarity of 1.35 mol H2So4 in 245 mL of solution?

Chemistry

1 answer:

vovikov84 [41]1 year ago

7 0

Answer:

5.51mol/L

Explanation:

Number of moles = 1.35moles

Volume of the solution = 245mL = 245*10^-3L = 0.245L

Molarity of a solution is the defined as the number of moles of a solute dissolved in 1L of the solution.

1.35 moles = 0.245L

X moles = 1L

X = (1.35 * 1) / 0.245

X = 5.51mol/L

The molarity of the solution is 5.51mol/L

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Answer:

The final volume is 39.5 L = 0.0395 m³

Explanation:

Step 1: Data given

Initial temperature = 200 °C = 473 K

Volume = 0.0250 m³ = 25 L

Pressure = 1.50 *10^6 Pa

The pressure reduce to 0.950 *10^6 Pa

The temperature stays constant at 200 °C

Step 2: Calculate the volume

P1*V1 = P2*V2

⇒with P1 = the initial pressure = 1.50 * 10^6 Pa

⇒with V1 = the initial volume = 25 L

⇒with P2 = the final pressure = 0.950 * 10^6 Pa

⇒with V2 = the final volume = TO BE DETERMINED

1.50 *10^6 Pa * 25 L = 0.950 *10^6 Pa * V2

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V2 = 39.5 L = 0.0395 m³

The final volume is 39.5 L = 0.0395 m³

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1 year ago

If charges flow very slowly through a metal, why does it not require several hours for a light to come on when you throw a switc

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The charges themselves may not move fast, but the force upon them does. The electric field set up by the battery or generator propagates through the wires at the speed of light.

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2 years ago

A sample of bismuth weighing 0.687 g was converted to bismuth chloride by reacting it first with HNO3, and then with HCI, follow

alisha [4.7K]

Answer:

The empirical formula is BiCl3

% Bi = 66.27 %

Explanation:

Step 1: Data given

Mass of bismuth = 0.687 grams

Mass of bismuth chloride produced = 1.032 grams

Molar mass of bismuth = 208.98 g/mol

Molar mass of bismuth chloride = 315.33 g/mol

Step 2: The balanced equation

Step 3: Calculate moles of Bi

Moles Bi = mass Bi / molar mass Bi

Moles Bi = 0.687 grams / 208.98 g/mol

Moles Bi = 0.00329 moles

Step 4: Calculate moles of Cl

Mass of Cl = 1.032 - 0.687 = 0.345 moles

Moles Cl = 0.345 moles / 35.45 g/mol

Moles Cl = 0.00973 moles Cl

Step 5: Calculate mol ratio

We divide by the smaller number of moles:

Bi: 0.00329 / 0.00329 = 1

Cl: 0.0097The empirical formula is BiCl33/0.00329 = 3

Step 6: Calculate molar mass of BiCl3

Molar mass = 208.98 + 3*35.45 = 315.33 g/mol

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% Bi = (208.98 / 315.33) * 100%

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1 year ago

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Answer:

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Explanation:

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