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Mkey [24]
2 years ago
9

A drug suspension decomposes by zero-order kinetics with a rate constant of 2 mg mL-1month-1. If the initial concentration is 10

0 mg mL-1, what is the shelf life (t10%)?
Chemistry
1 answer:
kramer2 years ago
7 0

Answer: 5 months

Explanation: <u>Rate</u> <u>Law</u> for a reaction is an equation relating the reaction rate of reactants. It is expressed as:

aA + bB → cC + dD

r=k[A]^{a}[B]^{b}

in which k is the rate constant of the reaction

<u>Zero-order</u> <u>Kinetics</u> is a chemical reaction in which the rate doesn't change with the variations in concentration of the reactants. At this state, it is possible to determine the final concentration by using:

[A]=-kt+[A_{0}]

<u>Shelf-Life</u> is the time required for 10% of a drug or material to desintegrate: it is the time necessary for A to desintegrate 90% of its original concentration.

Then, the shelf-life for the drug is

[A]=-kt+[A_{0}]

90=-2t+100

2t = 10

t = 5

Shelf-life for a drug which decomposes by zero-order kinetics with rate constant of 3mgmL^{-1}month^{-1} is 5 months

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The name "penicillin" is used for several closely-related antibiotics. A 1.2177 g sample of one of these compounds is burned, pr
masya89 [10]

<u>Answer:</u> The empirical formula for the given organic compound is C_7H_{11}O_2SN

<u>Explanation:</u>

The chemical equation for the combustion of hydrocarbon having carbon, hydrogen and oxygen follows:

S_vN_wC_xH_yO_z+O_2\rightarrow CO_2+H_2O+SO_2+NO

where, 'v', 'w' 'x', 'y' and 'z' are the subscripts of sulfur, nitrogen, carbon, hydrogen and oxygen respectively.

We are given:

Mass of CO_2=0.2829g

Mass of H_2O=0.1159g

Mass of SO_2=0.4503g

Mass of NO = 0.2109 g

We know that:

Molar mass of carbon dioxide = 44 g/mol

Molar mass of water = 18 g/mol

Molar mass of sulfur dioxide = 64 g/mol

Molar mass of nitrogen monoxide = 30 g/mol

  • <u>For calculating the mass of carbon:</u>

In 44 g of carbon dioxide, 12 g of carbon is contained.

So, in 2.1654 g of carbon dioxide, \frac{12}{44}\times 2.1654=0.590g of carbon will be contained.

  • <u>For calculating the mass of hydrogen:</u>

In 18 g of water, 2 g of hydrogen is contained.

So, in 0.6965 g of water, \frac{2}{18}\times 0.6965=0.077g of hydrogen will be contained.

  • <u>For calculating the mass of sulfur:</u>

In 64 g of sulfur dioxide, 32 g of sulfur is contained.

So, in 0.4503 g of sulfur dioxide, \frac{32}{64}\times 0.4503=0.225g of sulfur will be contained.

  • <u>For calculating the mass of nitrogen:</u>

In 30 g of nitrogen monoxide, 14 g of nitrogen is contained.

So, in 0.2109 g of nitrogen monoxide, \frac{14}{30}\times 0.2109=0.098g of nitrogen will be contained.

  • Mass of oxygen in the compound = (1.2177) - (0.590 + 0.077 + 0.225 + 0.098) = 0.2277 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{0.590g}{12g/mole}=0.049moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.077g}{1g/mole}=0.077moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{0.2277g}{16g/mole}=0.0142moles

Moles of Sulfur = \frac{\text{Given mass of Sulfur}}{\text{Molar mass of sulfur}}=\frac{0.225g}{32g/mole}=0.007moles

Moles of Nitrogen = \frac{\text{Given mass of nitrogen}}{\text{Molar mass of nitrogen}}=\frac{0.098g}{14g/mole}=0.007moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.007 moles.

For Carbon = \frac{0.049}{0.007}=7

For Hydrogen  = \frac{0.077}{0.007}=11

For Oxygen  = \frac{0.0142}{0.007}=2.03\approx 2

For Sulfur  = \frac{0.007}{0.007}=1

For Nitrogen  = \frac{0.007}{0.007}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O : S : N = 7 : 11 : 2 : 1 : 1

Hence, the empirical formula for the given compound is C_7H_{11}O_2S_1N_1=C_7H_{11}O_2SN

4 0
2 years ago
A sample of 508.4 grams of copper completely reacted with oxygen to form 572.4 grams of a copper oxide product. how many grams o
Svet_ta [14]

According to law of conservation of mass, mass can neither be destroyed nor created in a chemical reaction. Thus, sum of masses of reactants must be equal to sum of masses of products in a reaction.

The chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, sum of masses of Cu and oxygen gas should be equal to CuO formed.

2m_{Cu}+m_{O_{2}}=2m_{CuO}

Thus, mass of oxygen will be:

m_{O_{2}}=2(572.4-508.4)g=128 g

This can be further proved as follows:

The balanced chemical reaction is as follows:

2Cu+O_{2}\rightarrow 2CuO

Here, 2 moles of Cu completely reacts with 1 mole of O_{2} to give 2 moles of CuO.

Thus, 1 mole of Cu reacts with 0.5 moles of O_{2} .

The mass of Cu is 508.4 and molar mass is 63.546 g/mol, number of moles can be calculated as follows:

n=\frac{m}{M}=\frac{508.4 g}{63.546 g/mol}=8 mol

Thus, number of moles of  O_{2} reacting will be:

n_{O_{2}}=8\times 0.5 mol=4 mol

Molar mass of oxygen molecule is 32 g/mol thus, mass can be calculated as follows:

m=n×M=4 mol×32 g/mol=128 g/mol

This satisfies the law of conservation of mass.


7 0
2 years ago
One ATP molecule's hydrolysis releases 7.3 kcal/mol of energy (∆G = −7.3 kcal/mol of energy). If it takes 2.1 kcal/mol of energy
Oxana [17]

Answer:

One ATP molecule's hydrolysis can move 3 ions of Sodium (Na+) across the menbrane.

Explanation:

As you can see, the energy provided by ATP is enough for moving 3 ions of Na+. Each ion needs +2.1 kcal/mol of energy.

If we multiply by 3 the energy for moving across the membrane= +6.3 kcal/mol

By adding the energy from ATP:

ΔGTotal=6.3-7.3= -1 kcal/mol

7 0
2 years ago
Which choice below correctly completes the sentence? _______ reaches the Earth's surface through _______, then turns into ______
blondinia [14]

Answer:

d , before the molten rock becomes lava, it is first magma, and most people know that lava is ejected from volcanoes

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A major problem caused by humans is the contamination and depletion of _____ resources. A. solar B. water C. wind
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Water is the only one of these that would work by process of elimination.
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