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e-lub [12.9K]
2 years ago
9

Which graphic below shows the correct orientation of each water molecule when it is near the cl- ion in the aqueous solution?

Chemistry
1 answer:
andrew-mc [135]2 years ago
8 0
The question is missing the graphics required to answer which I have attached as an image.

There are four different representations of the orientation of water molecules around chloride anion. Let's first analyze the water molecule.

We have H-O-H as the structure of water. The oxygen atom is more electronegative than the hydrogen atoms, which results in a partial positive charge on the hydrogen atoms and a partial negative charge on the oxygen atom.

The chloride anion is a negative charge. Therefore, the water molecules should orient themselves with the hydrogen atoms facing the chlorine atom as the partial positive charge on the hydrogen atoms will be attracted to the negative charge of the chlorine atom.

The correct representation is shown in graph 3 which shows all hydrogen atoms facing the chlorine anion.

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A sample of gasoline contains various hydrocarbons, which comprise atoms of carbon, hydrogen, and oxygen. The hydrocarbons mix t
Naddika [18.5K]

Answer:

  • mixture
  • homogenous mixture  (of hydrocarbons)
  • compound

Explanation:

Mixture can be easily separated by physical methods. Homogeneity and heterogeneity of a mixture is determined by whether the components there in are in a single phase and evenly distributed or not.

A solution has a solute evenly dissolved in  solvent to form a liquid substance.

An element is the basic form of  substance which cannot be broke down into any other simpler unit.  

I hope this was helpful.

4 0
2 years ago
A student has a mixture of salt (NaCl) and sugar (C12H22O11). To determine the percent composition, the student measures out 5.8
ra1l [238]

Answer:

<u>1. Net ionic equation:</u>

  • Cl⁻(aq) +  Ag⁺(aq) → AgCl(s)

<u />

<u>2. Volume of 1.0M AgNO₃</u>

  • 41ml

Explanation:

1. Net ionic equation for the reaction of NaCl with AgNO₃.

i) Molecular equation:

It is important to show the phases:

  • (aq) for ions in aqueous solution
  • (s) for solid compounds or elements
  • (g) for gaseous compounds or elements

  • NaCl(aq) + AgNO₃(aq) → AgCl(s) + NaNO₃(aq)

ii) Dissociation reactions:

Determine the ions formed:

  • NaCl(aq) → Na⁺(aq) + Cl⁻(aq)
  • AgNO₃(aq) → Ag⁺(aq) + NO₃⁻(aq)
  • NaNO₃(aq) → Na⁺(aq) + NO₃⁻(aq)

iii) Total ionic equation:

Substitute the aqueous compounds with the ions determined above:

  • Na⁺(aq) + Cl⁻(aq) +  Ag⁺(aq) + NO₃⁻(aq) → AgCl(s) +  Na⁺(aq) + NO₃⁻(aq)

iv) Net ionic equation

Remove the spectator ions:

  • Cl⁻(aq) +  Ag⁺(aq) → AgCl(s) ← answer

2.  How many mL of 1.0 M AgNO₃ will be required to precipitate 5.84 g of AgCl

i) Determine the number of moles of AgNO₃

The reaction is 1 to 1: 1 mole of AgNO₃ produces 1 mol of AgCl

The number of moles of AgCl is determined using the molar mass:

  • number of moles = mass in grams / molar mass
  • molar mass of AgCl = 143.32g/mol
  • number of moles = 5.84g / (143.32g/mol) = 0.040748 mol

ii) Determine the volume of AgNO₃

  • molarity = number of moles of solute / volume of solution in liters

  • 1.0M = 0.040748mol / V

  • V = 0.040748mol / (1.0M) = 0.040748 liter

  • V = 0.040748liter × 1,000ml / liter = 40.748 ml

Round to two significant figures: 41ml ← answer

4 0
2 years ago
The target diol is synthesized in one step from 1-methylcyclopentene, but your lab partner exhausted the supply of that alkene.
andrezito [222]

Answer:

The reagents are CH_{3}CH_{3}O^{-},OsO_{4},NaHSO_{3}and H_{2}O.

Explanation:

1-Methylenecyclopentene is treated with HBr form 1-bromo-1-methylcyclopentane, which is treated with strong base ethoxide ion and forms 1-methylcyclopent-1-ene.

This alkene is treated with osmium tetraoxide in the presence of sodium bisulfite to form target product.

The chemical reaction is as follows.

4 0
2 years ago
The intrinsic solubility of sulfathiazole, an old antimicrobial, is 0.002 mol/l. it is a weak acid and its pka is 7.12. what is
lys-0071 [83]

The formula we will use is:

pH = 0.5 (pKa – log C)

where C is the concentration of sulfathiazole in molarity or mol / L

Since all values are given, we can compute directly for pH:

 

pH = 0.5 (7.12 – log 0.002)

<span>pH = 4.91</span>

4 0
2 years ago
In a first order reaction 40% of reactant gets converted into product in 30 minutes. What time would it require to convert 75% i
e-lub [12.9K]
56 minutes and 15 seconds I believe
5 0
2 years ago
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