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dlinn [17]
2 years ago
11

Which is a component of John Dalton’s atomic theory? The ratio of atoms in a compound is fixed. The atoms of different elements

are the same. An atom is a small particle of matter that can be broken down. A reaction can create or destroy atoms as well as rearrange them
Chemistry
2 answers:
leonid [27]2 years ago
6 0

Answer:

The right answer is A

Explanation:

marin [14]2 years ago
5 0
The English scientist John Dalton were one of the early scientists who paved the way to science, particularly in atomic chemistry. His atomic theory jumpstarted further developments made by J.J Thomson, Rutherford, Bohr, Schrodinger and many more. 

Dalton's atomic theory can be summarized in 5 key points:

1. Atoms are tiny, indivisible and indestructible particles of an element.
2. Atoms of different elements vary in size and mass.
3. Atoms of an element are uniform in size and mass.
4. Compounds are formulated by a fixed ratio of individual atoms of elements.
5. Reactions undergo by rearranging the atoms of the reactants to form the products.

From the choices, the acceptable answer would be: <span>The ratio of atoms in a compound is fixed. </span>
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Plseas help Calculate the amount of moles in 57.6 Liters of Carbon Dioxide.
slavikrds [6]
Convert 57.6 L to dm3 and divide it by 24
8 0
2 years ago
A 2.50-l flask contains a mixture of methane (ch4) and propane (c3h8) at a pressure of 1.45 atm and 20°c. when this gas mixture
Cerrena [4.2K]

Answer:- Mole fraction of methane in the original gas mixture is 0.854.

Solution:- From given volume, pressure and temperature, we could calculate the total moles of the gaseous mixture of methane and propane using ideal gas law as:

PV = nRT

n=\frac{PV}{RT}

V = 2.50 L

P = 1.45 atm

T = 20 + 273 = 293 K

Let's plug in the values in the equation:

n=(\frac{1.45*2.50}{0.0821*293})

n = 0.151

Let's say the solution has X moles of methane. Then moles of propane would be = (0.151 - X)

The combustion equations of methane and propane are:

CH_4+2O_2\rightarrow CO_2+2H_2O

C_3H_8+5O_2\rightarrow 3CO_2+4H_2O

From methane balanced equation, there is 1:1 mol ratio between methane and carbon dioxide. So, X moles of methane would produce X moles of carbon dioxide.

From balanced equation of propane, there is 1:3 mol ratio between propane and carbon dioxide. So, (0.151 - X) moles of propane would give 3(0.151 - X) moles of carbon dioxide.

So, total moles of carbon dioxide that we would get from methane and propane combustion are:

X + 3(0.151 - X)

From given data, 8.60 g of carbon dioxide are formed by the combustion of gas mixture.

moles of Carbon dioxide = 8.60g(\frac{1mol}{44g})

moles of carbon dioxide = 0.195 mol

Hence, 0.195 = X + 3(0.151 - X)

Let's solve this for X as:

0.195 = X + 0.453 - 3X

0.195 = 0.453 - 2X

2X = 0.453 - 0.195

2X = 0.258

X=\frac{0.258}{2}

X = 0.129

So, there are 0.129 moles of methane in the mixture.

moles of propane = 0.151 - 0.129 = 0.022

mole fraction of methane = \frac{moles of Methane}{total moles}

mole fraction of methane = \frac{0.129}{0.151}

mole fraction of methane = 0.854

Hence, the mole fraction of methane gas in the original gas mixture is 0.854.

6 0
2 years ago
Anyway, which is a spectator ion involved in the reaction of k2cro4(aq) and ba(no3)2(aq)?
marissa [1.9K]

Nitrate ions \text{NO}_3^{-} and potassium ions \text{K}^{+}.

<h3>Explanation</h3>

Potassium dichromate undergoes a double-decomposition reaction with barium nitrate to produce barium dichromate and potassium nitrate. The reaction is possible due to the low solubility of barium dichromate that precipitate out of the solution readily after its production.

Start with the balanced chemical equation for this process:

\text{K}_2\text{CrO}_4 \; (aq) + \text{Ba}(\text{NO}_3)_2 \; (aq) \to \text{Ba}(\text{CrO}_4)_2 \; (s) + 2 \; \text{KNO}_3 \; (aq)

Rewrite the chemical equation as an ionic one; express all soluble salts- those with state symbol (aq)- as their constituting ions while leaving the insoluble (s) intact.

2 \; \text{K}^{+}\; (aq)+ 2\; \text{CrO}_4^{-} \; (aq) + \text{Ba}^{2+} \; (aq) + 2 \; \text{NO}_3^{-} \; (aq) \\ \to \text{Ba}(\text{CrO}_4)_2 \; (s) + 2 \; \text{K}^{+} \; (aq) + 2 \; \text{NO}_3^{-} \; (aq)

\text{K}^{+} and \text{CrO}_4^{-} are found on both sides of the equation by the same quantity. The two ions thus took no part in the net reaction and act as spectator ions.

5 0
2 years ago
How can the existence of spectra help to prove that energy levels in atoms exist?
Liula [17]
The existence of spectra can help the existence of atoms by expanding and multiplying in the law of London Dispersion
6 0
2 years ago
What mass of steam at 100 C must be mixed with 150 gram of ice at its melting point, in a thermally insulated container, to prod
9966 [12]
The ice will require two forms of heat: latent to melt and sensible to be heated to 50 °C.
Q(ice) = ml + mCpΔT
= 150 x 333 + 150 x 4.18 x 50
= 85950 Joules
The mass of steam must release this much energy in two forms: latent to fuse into water and then sensible to cool to 50 °C.
85950 = m(2256) + 4.18 x 50 x m
m = 34.9 grams of steam.
6 0
2 years ago
Read 2 more answers
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