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2 years ago

What mass of 2-bromopropane could be prepared from 25.5 g of propene? Assume a 100% yield of product.

Chemistry

1 answer:

Mamont248 [21]2 years ago

5 0

Answer:

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene

Explanation:

$C_3H_6+HBr\rightarrow C_3H_7Br$

Moles of propene = $\frac{25.5 g}{39 g/mol}=0.6538 mol$

According to reaction, 1 mole of propene gives 1 mole of propane.

Then 0.6538 moles of bromo-propane will give:

$0.6538 mol\times 120 g/mol=78.46 g$

78.46 grams of 2-bromopropane could be prepared from 25.5 g of propene.

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Suppose you are titrating vinegar, which is an acetic acid solution of unknown strength, with a sodium hydroxide solution accord

Marina CMI [18]

Answer:

$M_{acid}=0.563M$

Explanation:

Hello there!

In this case, given the neutralization of the acetic acid as a weak one with sodium hydroxide as a strong base, we can see how the moles of the both of them are the same at the equivalence point; thus, it is possible to write:

$M_{acid}V_{acid}=M_{base}V_{base}$

Thus, we solve for the molarity of the acid to obtain:

$M_{acid}=\frac{M_{base}V_{base}}{V_{acid}} \\\\ M_{acid}=\frac{33.98mL*0.1656M}{10.0mL}\\\\ M_{acid}=0.563M$

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5 0

1 year ago

A sodium atom has an electron configuration of 1s22s22p63s1.if the sodium atom becomes ionized, its new electron configuration w

dezoksy [38]

Answer:

Neon

Explanation:

1s² 2s² 2p⁶ 3s¹ or [Ne] 3s¹

The outer most shell is the 3s¹.

For this atom to achieve stability, if it loses the electron in the 3s shell, it would resemble an inert element with a complete octet configuration. Therefore, the atom would be like:

1s² 2s² 2p⁶ which is the configuration of Ne

8 0

1 year ago

A gas occupies a volume of 72 ml at 400 k and 800 torr. if the temperature drops to 200 k and the pressure changes to 400 torr,

satela [25.4K]

We are tasked to solve for the volume of the gas that occupies when pressure and temperature changes to 400 Torr and 200 Kelvin from Torr and 400 Kelvin. We can use ideal gas law assuming constant gas composition and close system. The solution is shown below:
P1V1 / T1 = P2V2 / T2
V2 = P1V1T2 / T1P2
V2 = 800*72*200 / 400*400
V2 = 72 ml

The answer for the volume is 72 ml.

7 0

1 year ago

In the heat equation, what does Q represent? heat required to raise the temperature specific heat of the substance mass of the s

MaRussiya [10]

Answer: heat required to raise the temperature

Explanation: Heat equation is represented as:

$Q= m\times c\times \Delta T$

Q= heat required to raise the temperature

m= mass of the substance

c = heat capacity of substance

$\Delta T={\text{Change in temperature}}$

7 0

2 years ago

Read 2 more answers

Determine whether the stopcock should be completely open, partially open, or completely closed for each activity involved with t

densk [106]

Answer:

Close to the calculated endpoint of a titration - Partially open

At the beginning of a titration - Completely open

Filling the buret with titrant - Completely closed

Conditioning the buret with the titrant - Completely closed

Explanation:

'Titration' is depicted as the process under which the concentration of some substances in a solution is determined by adding measured amounts of some other substance until a rection is displayed to be complete.

As per the question, the stopcock would remain completely open when the process of titration starts. After the buret is successfully placed, the titrant is carefully put through the buret in the stopcock which is entirely closed. Thereafter, when the titrant and the buret are conditioned, the stopcock must remain closed for correct results. Then, when the process is near the estimated end-point and the solution begins to turn its color, the stopcock would be slightly open before the reading of the endpoint for adding the drops of titrant for final observation.

3 0

1 year ago