Question

What mass of 2-bromopropane could be prepared from 25.5 g of propene? Assume a 100% yield of product.

Answer 1

Answer:

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene

Explanation:

$C_3H_6+HBr\rightarrow C_3H_7Br$

Moles of propene = $\frac{25.5 g}{39 g/mol}=0.6538 mol$

According to reaction, 1 mole of propene gives 1 mole of propane.

Then 0.6538 moles of bromo-propane will give:

$0.6538 mol\times 120 g/mol=78.46 g$

78.46 grams of  2-bromopropane could be prepared from 25.5 g of propene.