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andre [41]
2 years ago
6

What do pH and conductivity have in common?

Chemistry
2 answers:
Anna71 [15]2 years ago
8 0
PH and conductivity have no common rekationship
rjkz [21]2 years ago
5 0
PH indicates how acidic or alkaline a substance is and conductivity the ability of substance to conduct electricity... the higher or lower pH the higher the conductivity of the substance.
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When 0.610 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °C to 50.50
PtichkaEL [24]

Answer:

(ΔHrxn)= 0.15kJ/mol

Explanation:

(ΔHrxn) = mc∆t

=0.00061×9.84×(50.5-25)

= 0.153kJ/mol

8 0
2 years ago
When a stable diatomic molecule spontaneously forms from its atoms, what are the signs of Delta H, Delta S, and Delta G? A. + +
Neko [114]
H will definitely be positive because a bond is always more stable than no bond surely if it is a sigma bond.
For G you can't really know because you don't know how much energy is provided by the bond and if it outways the loss in disorder.


The reaction will become more spontaneous with a lower temperature because H tells you the reaction is exotherm
3 0
2 years ago
Iron (Fe) undergoes an allotropic transformation at 912°C: upon heating from a BCC (α phase) to an FCC (γ phase). Accompanying t
Alex

Answer:

false thought ia ion of neon = clarity active

Explanation:

x = 81254 \: and \: y = 91284

8 0
2 years ago
Read 2 more answers
Consider the following chemical reaction: CO (g) + 2H2(g) ↔ CH3OH(g) At equilibrium in a particular experiment, the concentratio
AlexFokin [52]

Answer:

The equilibrium concentration of CH₃OH is 0.28 M

Explanation:

For the reaction: CO (g) + 2H₂(g) ↔ CH₃OH(g)

The equilibrium constant (Keq) is given for the following expresion:

Keq= \frac{(CH3OH)}{(CO) x (H2)^{2}} =14.5

Where (CH3OH), (CO) and (H2) are the molar concentrations of each product or reactant.

We have:

(CH3OH)= ?

(CO)= 0.15 M

(H2)= 0.36 M

So, we only have to replace the concentrations in the equilibrium constant expression to obtain the missing concentration we need:

14.5= \frac{(CH_{3}OH) }{(0.15 M) x (0.36 M) ^{2} }

14.5 x (0.15 M) x (0.36)^{2} = (CH₃OH)

0.2818 M = (CH₃OH)

6 0
2 years ago
You can identify a metal by carefully determining its density. A 8.44 g piece of an unknown metal is 1.25 cm long, 2.50 cm wide,
Dafna1 [17]

Answer: Aluminum, 2.70 g/cm^3

Explanation:

Density is defined as the mass contained per unit volume.  It is characteristic of a substance.

Density=\frac{mass}{Volume}

Given : Mass of object = 8.44 grams

Volume of object=length\times breadth\times height=1.25cm\times 2.50cm\times 1.0cm=3.125cm^3

Putting in the values we get:

Density=\frac{8.44g}{3.125cm^3}=2.70g/cm^3

Thus density of the object will be 2.70 g/cm^3  which matches that of aluminium.

4 0
2 years ago
Read 2 more answers
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