Basis: 100 mL solution
From the given density, we calculate for the mass of the solution.
density = mass / volume
mass = density x volume
mass = (1.83 g/mL) x (100 mL) = 183 grams
Then, we calculate for the mass H2SO4 given the percentage.
mass of H2SO4 = (183 grams) x (0.981) = 179.523 grams
Calculate for the number of moles of H2SO4,
moles H2SO4 = (179.523 grams) / (98.079 g/mol)
moles H2SO4 = 1.83 moles
Molarity:
M = moles H2SO4 / volume solution (in L)
= 1.83 moles / (0.1L ) = 18.3 M
Molality:
m = moles of H2SO4 / kg of solvent
= 1.83 moles / (183 g)(1-0.983)(1 kg/ 1000 g) = 588.24 m
Let's look at the molar weight of the answers:
NO is 30 g/mol
NO2 is 46
N2O is 44
N2O4 is 124
<span>We have the grams of the product, so we need the moles in order to calculate the molar weight. We us PV=nRT for this, assuming standard temperature and pressure. </span>
You were given the liters (.120L)
Std pressure is 1 atmosphere
You're looking for n, the number of moles
<span>Temp is 293.15 kelvin, thats standard </span>
And r is the gas constant in liters-atm per mol kelvin
(.120 liters)(1atm)=n(293.15K)(.08206)
Solving for n is .0049883835 mol
<span>.23g divided by .0049883 mol is about 46g/mol. You're answer is B I think, NO2
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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Compound X is an isomer of butane with different chain types. It is either straight chain or bend chain.
Answer:
1.123x10⁻⁴ moles of alanine
Explanation:
In order to convert grams of alanine into moles, <em>we need to know its molecular weight</em>:
The formula for alanine is C₃H₇NO₂, meaning <u>its molecular weight would be</u>:
- 12*3 + 7*1 + 14 + 16*2 = 89 g/mol
Then we <u>divide the sample mass by the molecular weight</u>, to do the conversion:
- 1.0x10⁻² g ÷ 89 g/mol = 1.123x10⁻⁴ moles
Answer : The concentration of 
in the solution is, 
Explanation :
First we have to calculate the volume of aqueous solution that is water.
Density of water = 1.00 g/mL
Mass of water = 2400 g
Now we have to calculate the concentration of ammonia solution.
Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.
Formula used :
Molar mass of = 17 g/mole
Now put all the given values in this formula, we get:
Therefore, the concentration of in the solution is,
