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Aliun [14]
1 year ago
14

A 5-ounce cup of raspberry yogurt contains 5.0 g of protein, 3.0 g of fat, and 13.3 g of carbohydrate. The fuel values for prote

in, fat, and carbohydrate are 17, 38, and 17 kJ/g, respectively. What is the fuel value of this yogurt in Calories?
Chemistry
1 answer:
castortr0y [4]1 year ago
6 0

Answer:

as it has 17000 joules and 1 calorie has 4184 joules, this yogurt serving has 4.06 calories

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Eddie is going to do an experiment to find out which freezes more easily—distilled water or salt water. In what order should he
mel-nik [20]

1. Make a Prediction

2. Fill both beakers with water

3. Dissolve salt in one of the beakers

4. Place both in the freezer and observe

5. Write a report

(Always make the prediction first! That's a hypothesis!)

4 0
2 years ago
Read 2 more answers
50cm3 of sodium hydroxide solution was titrated against a solution of sulfuric acid. The concentration of the sodium hydroxide s
miskamm [114]

Answer:

49 g/L is the concentration of the acid

Explanation:

Firstly, we proceed to write the equation of reaction.

2NaOH + H2SO4 ——-> Na2SO4 + 2H2O

We can see that 1 mole of the base reacted with two moles of the acid.

kindly note that dm^3 is same as liter

Firstly, we need to get the concentration of the reacted sulphuric acid in g/L

we use the simple titration equation below;

CaVa/CbVb = Na/Nb

From the question;

Ca = ?

Va = 25 cm^3

Cb = 20 g/L

we convert this to concentration in mol/L

Mathematically, that is concentration in g/L divided by molar mass in g/mole

molar mass of NaOH = 40 g/mol

so we have; 20g/L / 40 = 0.5 mol/L

Vb = 50 cm^3

Na = 1

Nb = 2

Where C represents concentrations, V volumes and N , number of moles

Now, substitute the values;

Ca * 25/0.5 * 50 = 1/2

25Ca/25 = 0.5

So Ca = 0.5 mol/L

Now to get the concentration of H2SO4 in g/L

What we do is to multiply the concentration in mol/L by molar mass in g/mol

That would be 0.5 * 98 = 49 g/L

4 0
2 years ago
Only one isotope of this element occurs in nature. one atom of this isotope has a mass of 9.123 ✕ 10-23 g. identify the element
o-na [289]

The atom has only one isotope which means 100 % of same atom is present in nature. The atomic mass of an element is the number of times an atom of that element is heavier than an atom of carbon taken as 12. Mass of one atom of that isotope is 9.123 ✕ 10⁻²³ g, so mass of one mole of atom that is Avogadro's number of atom is 6.023 X 10²³  X 9.123 X 10⁻²³ g=54.94 g = 55 g (approximate).

So, the atom having atomic mass 55 will be Cesium (Cs). Only one isotope of Cesium is stable in nature.

5 0
1 year ago
Read 2 more answers
Industrial production of nitric acid, which is used in many products including fertilizers and explosives, approaches 10 billion
mylen [45]

Answer: 9.361\times 10^{4} kJ

Explanation:

The balanced chemical equation :

4NH_3(g)+5O_2(g)\rightarrow 4NO(g)+6H_2O(g)  \Delta H^0_{rxn}=-902.0kJ

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{7.056\times 10^3g}{17g/mol}=415.1moles

According to stoichiometry:

4 moles of NH_3 produces = 902.0 kJ of energy

415.1 moles of NH_3 produces =\frac{902.0}{4}\times 415.1=9.361\times 10^{4} kJ of energy

Thus the change in enthalpy is 9.361\times 10^{4} kJ

5 0
2 years ago
A system fitted with a piston expands when it absorbs 52.7J of heat from the surroundings. The piston is working against a press
Allushta [10]

Answer: The initial volume of the system is 60.29 L.

Explanation:

According to the first law of thermodynamics,

      \Delta U = Q - W

As it is given that heat is being added to the system so, \Delta H will be positive. And, work done on the system is negative and work done by the system is positive.

So here, \Delta U = -107.4 J

                    Q = 52.7 J

                    P = 0.693 atm

And,     W = PdV

or,        W = P (V_{final} - V_{initial})

So,       \Delta U = Q - P (V_{final} - V_{initial})

            -107.4 J = 52.7 J - 0.693 \times 101.325 (63.2 - V)

            -160.1 = -43.79 - 70.21 (63.2 - V)

           63.2 - V = \frac{160.1 + 43.79}{70.21}

                  - V =  2.90 - 63.2

                     V = 60.29 L

Thus, we can conclude that the initial volume of the system is 60.29 L.

6 0
1 year ago
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