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kupik [55]
2 years ago
14

A system fitted with a piston expands when it absorbs 52.7J of heat from the surroundings. The piston is working against a press

ure of 0.693 atm. the final volume is 63.2L. what was the initial volume of the system if the internal energy of the system decreased by 107.4J?
Chemistry
1 answer:
Allushta [10]2 years ago
6 0

Answer: The initial volume of the system is 60.29 L.

Explanation:

According to the first law of thermodynamics,

      \Delta U = Q - W

As it is given that heat is being added to the system so, \Delta H will be positive. And, work done on the system is negative and work done by the system is positive.

So here, \Delta U = -107.4 J

                    Q = 52.7 J

                    P = 0.693 atm

And,     W = PdV

or,        W = P (V_{final} - V_{initial})

So,       \Delta U = Q - P (V_{final} - V_{initial})

            -107.4 J = 52.7 J - 0.693 \times 101.325 (63.2 - V)

            -160.1 = -43.79 - 70.21 (63.2 - V)

           63.2 - V = \frac{160.1 + 43.79}{70.21}

                  - V =  2.90 - 63.2

                     V = 60.29 L

Thus, we can conclude that the initial volume of the system is 60.29 L.

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Analysis of the water content of a lake found in the desert showed that it contained 16.6 percent chloride ion, and had a densit
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Answer : The molarity of the chloride ion in the water is, 5.75 M

Explanation :

As we are given that 16.6 % chloride ion that means 16.6 grams of chloride ion present 100 grams of solution.

First we have to calculate the volume of solution.

\text{Volume of solution}=\frac{\text{Mass of solution}}{\text{Density of solution}}

\text{Volume of solution}=\frac{100g}{1.23g/mL}=81.3mL

Now we have to calculate the molarity of chloride ion.

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Formula used :

\text{Molarity}=\frac{\text{Mass of chloride ion}\times 1000}{\text{Molar mass of chloride ion}\times \text{Volume of solution (in mL)}}

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8 0
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PLEASE HELP!!!!!!!!!!!!!
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Answer:

Pd(O2C2H3)2

Explanation:

<u>Percentage composition of elements in the compound:</u>

Pd= 47.40%

O=28.50%

C=21.40%

H= 2.69%

<u>Molar mass of each element</u>

Pd= 106g/mol

O= 16g/mol

C= 12g/mol

H= 1g/mol

Step 1

Find the moles of each element in 100g sample using the formula

no. of moles(n)=mass/molar mass

<u>For Pd:</u> 47.40g/106g/mol

      n=   0.447 moles

<u>For O:</u> 28.50/16

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<u>For C:</u> 21.40/12

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<u>For H:</u> 2.69/1

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Step 2

Now divide the no. of moles separately by the smallest number of moles. Smallest number of moles is <em>0.447</em>

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C= 1.78/0.447

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The probable molecular formula is Pd(O_{2}C_{2}H_{3})2

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