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2 years ago

Select the simplest mole ratio for each substance. Glucose (C6H12O6): Sulfuric acid (H2SO4): Butene (C4H8):

Chemistry

2 answers:

Rom4ik [11]2 years ago

8 0

Answer:

1. In Glucose: C : H : O = 1 : 2 : 1

2. In Sulfuric acid: H : S : O = 2 : 1 : 4

3. In Butene: C : H = 1 : 2

Explanation:

Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.

In Glucose, $(C_6H_{12}O_6)$

Moles of Carbon atom = 6

Moles of Hydrogen atom = 12

Moles of Oxygen atom = 6

Mole ratio of the atoms: C : H : O :: 6 : 12 : 6

Making this, the simplest mole ratio C : H : O = 1 : 2 : 1

In Sulfuric acid, $(H_2SO_4)$

Moles of Sulfur atom = 1

Moles of Hydrogen atom = 2

Moles of Oxygen atom = 4

Mole ratio of the atoms: H : S : O = 2 : 1 : 4

In Butene, $(C_4H_8)$

Moles of Carbon atom = 4

Moles of Hydrogen atom = 8

Mole ratio of the atoms: C : H = 1 : 2

iogann1982 [59]2 years ago

3 0

Answer:

c:h:O=1:2;1

h2so4=1;2

ch=1;2

Explanation:

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Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution

Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

$\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}$

or,

$\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}$

First we have to calculate the equivalent weight of solute.

Molar mass of solute $PO_4^{3-}$ = 94.97 g/mole

$\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq$

Now we have to calculate the normality of solution.

$\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L$

Therefore, the normality of the solution is, 30.006 N

5 0

1 year ago

You prepare a standard by weighing 10.751 mg of compound X into a 100 mL volumetric flask and making to volume. You further dilu

ArbitrLikvidat [17]

Answer:

0.12693 mg/L

Explanation:

First we calculate the concentration of compound X in the standard prior to dilution:

10.751 mg / 100 mL = 0.10751 mg/mL

Then we calculate the concentration of compound X in the standard after dilution:

0.10751 mg/mL * 5 mL / 25 mL = 0.021502 mg/L

Now we calculate the concentration of compound X in the sample, using the known concentration of standard and the given areas:

2582 * 0.021502 mg/L ÷ 4374 = 0.012693 mg/L

Finally we calculate the concentration of X in the sample prior to dilution:

0.012693 mg/L * 50 mL / 5 mL = 0.12693 mg/L

4 0

1 year ago

How many chloride ions are in 0.486 moles of chloride ions?

svetlana [45]

Answer:

Since in a chloride ion, we have an additional electron

you might think that it will affect the mass but the mass of an electron is almost negligible so we will ignore that

Amount of ions in 1 mol = 6.022 * 10^23

Amount of ions in 0.486 moles = 0.486 * (6.022*10^23)

Amunt of ions in 0.486 moles = 2.9 * 10^23 ions

Hence, option 1 is correct

6 0

1 year ago

What is the fraction of the hydrogen atom's mass (11h) that is in the nucleus? the mass of proton is 1.007276 u, and the mass of

ololo11 [35]

Hello there!

To determine the fraction of the hydrogen atom's mass that is in the nucleus, we have to keep in mind that a Hydrogen atom has 1 proton and 1 electron. Protons are in the nucleus while electrons are in electron shells surrounding the nucleus. The mass of the nucleus will be equal to the mass of 1 proton and we can express the fraction as follows:

$Mass Fraction= \frac{mass 1 Proton}{mass H atom} = \frac{1,007276 u}{1,007825}=0,9995$

So, the fraction of the hydrogen atom's mass that is in the nucleus is 0,9995. That means that almost all the mass of this atom is at the nucleus.

Have a nice day!

3 0

2 years ago

What is the product of one equivalent of phosphorus and three equivalents of hydrogen? Draw it's

yulyashka [42]

This name is phosphine flammable , toxic gas colourless
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6 0

2 years ago