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zhuklara [117]
2 years ago
14

Select the simplest mole ratio for each substance. Glucose (C6H12O6): Sulfuric acid (H2SO4): Butene (C4H8):

Chemistry
2 answers:
Rom4ik [11]2 years ago
8 0

<u>Answer:</u>

1. In Glucose: C : H : O = 1 : 2 : 1

2. In Sulfuric acid: H : S : O = 2 : 1 : 4

3. In Butene: C : H = 1 : 2

<u>Explanation:</u>

Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.

  • In Glucose, (C_6H_{12}O_6)

Moles of Carbon atom = 6

Moles of Hydrogen atom = 12

Moles of Oxygen atom = 6

Mole ratio of the atoms: C : H : O :: 6 : 12 : 6

Making this, the simplest mole ratio C : H : O = 1 : 2 : 1

  • In Sulfuric acid, (H_2SO_4)

Moles of Sulfur atom = 1

Moles of Hydrogen atom = 2

Moles of Oxygen atom = 4

Mole ratio of the atoms: H : S : O = 2 : 1 : 4

  • In Butene, (C_4H_8)

Moles of Carbon atom = 4

Moles of Hydrogen atom = 8

Mole ratio of the atoms: C : H = 1 : 2

iogann1982 [59]2 years ago
3 0

Answer:

c:h:O=1:2;1

h2so4=1;2

ch=1;2

Explanation:

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A sample of krypton has a volume of 6.00 L, and the pressure is 0.960 atm. If the final temperature is 55.0°C, the final volume
MissTica

193.38 K was the initial temperature of the krypton.

Explanation:

Data given:

Initial volume of the krypton gas = 6 litres

initial pressure of the krypton gas = 0.960 atm

initial temperature of the krypton gas = ?

final volume of the krypton gas  = 7.70 litres

final pressure of the Krypton gas  = 1.25 atm

final temperature of the krypton gas = 55 degrees or 273.25+55 = 323.15 K

Applying the  Combined Gas Laws:

\frac{P1V1}{T1} = \frac{P2V2}{T2}

Rearranging the equation:

T1  = \frac{P1V1T2}{P2V2}

Putting the value in the equation:

T1 = \frac{0.960 X 6 X 323.15}{1.25 X 7.70}

T1 = 193.38 K

Initial temperature of the krypton gas is 193.78 K

5 0
2 years ago
During this reaction, p4 + 5o2 → p4o10, 0.800 moles of product was made in 15.0 seconds. what is the rate of reaction? 56.8 g/mi
Eduardwww [97]
The solution for this problem would be:
The mass of P4O10 is computed by: 0.800 mol x 284 g/mol = 227g t = 15.0 s ( 1 min / 60 s) = 0.25 min 
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3 0
2 years ago
A sample of gas has a volume of 5.79 L at 25C and 518. What will be the volume of this gas at STP
Drupady [299]

Answer:

V2 = 389mL

Explanation:

At STP: P=760 torr and T=273K.

To solve this question, we could use Charles' law since both the number of mole and pressure are constant:

V1T1=V2T2

⇒V2=T2×V1T1

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2 years ago
A gas that has a volume of 28 liters, a temperature of 45C, And an unknown pressure has its volume increased to 34 liters and it
patriot [66]

Answer:

P1 = 2.5ATM

Explanation:

V1 = 28L

T1 = 45°C = (45 + 273.15)K = 318.15K

V2 = 34L

T2 = 35°C = (35 + 273.15)K = 308.15K

P1 = ?

P2 = 2ATM

applying combined gas equation,

P1V1 / T1 = P2V2 / T2

P1*V1*T2 = P2*V2*T1

Solving for P1

P1 = P2*V2*T1 / V1*T2

P1 = (2.0 * 34 * 318.15) / (28 * 308.15)

P1 = 21634.2 / 8628.2

P1 = 2.5ATM

The initial pressure was 2.5ATM

3 0
2 years ago
If you weigh 100 kg, how much would you weigh if all the water were removed from your body? A65 kg B45 kg C50 kg D35 kg
Mekhanik [1.2K]

Answer:

B. 45k

The human body is about 60 to 70% water.

(:

5 0
2 years ago
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