<u>Answer:</u>
1. In Glucose: C : H : O = 1 : 2 : 1
2. In Sulfuric acid: H : S : O = 2 : 1 : 4
3. In Butene: C : H = 1 : 2
<u>Explanation:</u>
Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.
Moles of Carbon atom = 6
Moles of Hydrogen atom = 12
Moles of Oxygen atom = 6
Mole ratio of the atoms: C : H : O :: 6 : 12 : 6
Making this, the simplest mole ratio C : H : O = 1 : 2 : 1
Moles of Sulfur atom = 1
Moles of Hydrogen atom = 2
Moles of Oxygen atom = 4
Mole ratio of the atoms: H : S : O = 2 : 1 : 4
Moles of Carbon atom = 4
Moles of Hydrogen atom = 8
Mole ratio of the atoms: C : H = 1 : 2
25 g of NH₃ will produce 47.8 g of (NH₄)₂S
<u>Explanation:</u>
2 NH₃ + H₂S ----> (NH₄)₂S
Molecular weight of NH₃ = 17 g/mol
Molecular weight of (NH₄)₂S = 68 g/mol
According to the balanced reaction:
2 X 17 g of NH₃ produces 68 g of (NH₄)₂S
1 g of NH₃ will produce g of (NH₄)₂S
25g of NH₃ will produce of (NH₄)₂S
= 47.8 g of (NH₄)₂S
Therefore, 25 g of NH₃ will produce 47.8 g of (NH₄)₂S
Given reaction represents dissociation of bromine gas to form bromine atoms
Br2(g) ↔ 2Br(g)
The enthalpy of the above reaction is given as:
ΔH = ∑n(products)Δ - ∑n(reactants)Δ
where n = number of moles
Δ= enthalpy of formation
ΔH = [2*ΔH(Br(g)) - ΔH(Br2(g))] = 2*111.9 - 30.9 = 192.9 kJ/mol
Thus, enthalpy of dissociation is the bond energy of Br-Br = 192.9 kJ/mol