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zhuklara [117]
2 years ago
14

Select the simplest mole ratio for each substance. Glucose (C6H12O6): Sulfuric acid (H2SO4): Butene (C4H8):

Chemistry
2 answers:
Rom4ik [11]2 years ago
8 0

<u>Answer:</u>

1. In Glucose: C : H : O = 1 : 2 : 1

2. In Sulfuric acid: H : S : O = 2 : 1 : 4

3. In Butene: C : H = 1 : 2

<u>Explanation:</u>

Mole ratio is defined as the ratio of amounts in moles present in a compound. Simplest mole ratio basically means that the moles are present in the least whole number ratio.

  • In Glucose, (C_6H_{12}O_6)

Moles of Carbon atom = 6

Moles of Hydrogen atom = 12

Moles of Oxygen atom = 6

Mole ratio of the atoms: C : H : O :: 6 : 12 : 6

Making this, the simplest mole ratio C : H : O = 1 : 2 : 1

  • In Sulfuric acid, (H_2SO_4)

Moles of Sulfur atom = 1

Moles of Hydrogen atom = 2

Moles of Oxygen atom = 4

Mole ratio of the atoms: H : S : O = 2 : 1 : 4

  • In Butene, (C_4H_8)

Moles of Carbon atom = 4

Moles of Hydrogen atom = 8

Mole ratio of the atoms: C : H = 1 : 2

iogann1982 [59]2 years ago
3 0

Answer:

c:h:O=1:2;1

h2so4=1;2

ch=1;2

Explanation:

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3 H2SO4 + 2 Al(OH)3 → Al2(SO4)3 + 6 H2O

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The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ΔH, ΔS, a
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The question is incomplete, the complete question is;

The normal boiling point of acetic acid is 118.1°C. If a sample of the acetic acid is at 125.2°C, predict the signs of ∆H, ∆S, and ∆G for the boiling process at this temperature.

A. ∆H > 0, ∆S > 0, ∆G < 0

B. ∆H > 0, ∆S > 0, ∆G > 0

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A. ∆H > 0, ∆S > 0, ∆G < 0

Explanation:

During boiling, a liquid is converted to vapour. This is a phase change for which heat is absorbed because energy must be taken in to break the intermolecular bonds in the liquid before it can be converted to a gas. Hence ∆H>0

Secondly, a phase change from liquid to gas leads to an increase in entropy hence ∆S>0.

Thirdly, the process is spontaneous. For every spontaneous process ∆G<0

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39.1+35.5+64 = 138.6

6 0
2 years ago
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