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ale4655 [162]
2 years ago
13

By mistake, a quart of oil was dumped into a swimming pool that measures 25.0 m by 30.0 m. The density of the oil was 0.750 g/cm

3. Assuming the oil spread into a uniform, thin layer over the water, how thick was the oil slick?
Chemistry
1 answer:
kondor19780726 [428]2 years ago
3 0

The oil slick thick = 1.256 x 10⁻⁴ cm

<h3>Further explanation</h3>

Volume is a derivative quantity derived from the length of the principal

The unit of volume can be expressed in liters or milliliters or cubic meters

The conversion is

1 cc = 1 cm3

1 dm = 1 Liter

1 L = 1.06 quart

<em>so for 1 quart = 0.943 L</em>

\tt 0.943~L=0.943\times 10^{-3}m^3

Volume of oil dumped = volume of swimming pool

\tt 0.943\times 10^{-3}~m^3=25\times 30\times h(h=thick)\\\\h=\dfrac{0.943\times 10^{-3}}{750~m^2}=1.257\times 10^{-6}~m=\boxed{\bold{1.256\times 10^{-4}~cm}}

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A 500 gram cube of lead is heated from 25 °C to 75 °C. How much energy was required to heat the lead? The specific heat of lead
Ludmilka [50]

Answer:

The energy required is 3225 Joules.

Explanation:

Given,

mass of lead cube = 500 grams

T₁ = 25°C

T₂ = 75°C

specific heat of lead = 0.129 J/g°C

Energy required to heat the lead can be found by using the formula,

Q = (mass) (ΔT) (Cp)

Here, ΔT = T₂ - T₁ = 75 - 25 = 50

Substituting the values,

Q = (500)(50)(0.129)

Q = 3225 Joules.

Therefore, energy required is 3225 J.

3 0
2 years ago
Why is a ylid a stable nucleophile? Select all that apply. Group of answer choices The proximity of the positively charged phosp
pogonyaev

Answer:

1)The proximity of the positively charged phosphorous and negatively charged carbon stabilizes the charges.

2) Inductive effects and resonance stabilize the negative charge

Explanation:

both atoms have full octets of electrons( I.e Carbon and say phosphorus). The result can be viewed as a structure in which two adjacent atoms are connected by both a covalent and an ionic bond; normally written X+–Y−. Ylides are thus 1,2-dipolar compounds, and a subclass of zwitterions

6 0
1 year ago
Determine the overall charge on particles with the subatomic makeups given.
Gwar [14]

Answer:

The correct solution will be "+3".

Explanation:

The given values are:

Number of protons

= 13

Number of neutrons

= 14

Number of electrons

= 10

As we know,

⇒  Charge = Number \ of \ protons - Number \ of \ electrons

On putting the estimated values, we get

⇒               =13 - 10

⇒               =+3

5 0
2 years ago
How many liters of a 0.225 M solution of KI are needed to contain 0.935 moles of KI?
Katyanochek1 [597]

Answer:

4.16L

Explanation:

From the question given, we obtained the following data:

Molarity = 0.225 M

Number of mole of KI = 0.935mole

Volume =?

Molarity = mole / Volume

Volume = mole /Molarity

Volume = 0.935/0.225

Volume = 4.16L

Therefore, 4.16L of KI is needed.

6 0
2 years ago
Select the valid ways to make an ammonia/ammonium buffer for use in the laboratory. Mix equal volumes of 1 M NH3 and 0.01 M NH 4
mrs_skeptik [129]

Answer:

The answer is "Option b and Option c".

Explanation:

This buffer is a buffer of ammonia and ammonium ion. Thus it requires the solution NH_3 \ \ and \ \ NH_4^{+}.

In point 1:

The solution containing NH_3 \ \ and \ \ NH_4^{+} at 1M concentration would be given by mixing the two solutions. Thus, this buffer is a legitimate route.

In point 2:

It gives the ions you want but they are not the same.

In point 3:

1 M NH_3 and 1 MHCl volume would not produce the same NH_3 \ \ and \ \ NH_4^{+} concentrations. Therefore, this buffer isn't a valid route.

In point 4:

Some 1 M NH_3 volume and half HCl . This offers the same rate as half.

7 0
1 year ago
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