Answer:
The energy required is 3225 Joules.
Explanation:
Given,
mass of lead cube = 500 grams
T₁ = 25°C
T₂ = 75°C
specific heat of lead = 0.129 J/g°C
Energy required to heat the lead can be found by using the formula,
Q = (mass) (ΔT) (Cp)
Here, ΔT = T₂ - T₁ = 75 - 25 = 50
Substituting the values,
Q = (500)(50)(0.129)
Q = 3225 Joules.
Therefore, energy required is 3225 J.
Answer:
1)The proximity of the positively charged phosphorous and negatively charged carbon stabilizes the charges.
2) Inductive effects and resonance stabilize the negative charge
Explanation:
both atoms have full octets of electrons( I.e Carbon and say phosphorus). The result can be viewed as a structure in which two adjacent atoms are connected by both a covalent and an ionic bond; normally written X+–Y−. Ylides are thus 1,2-dipolar compounds, and a subclass of zwitterions
Answer:
The correct solution will be "+3".
Explanation:
The given values are:
Number of protons
= 13
Number of neutrons
= 14
Number of electrons
= 10
As we know,
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
Answer:
4.16L
Explanation:
From the question given, we obtained the following data:
Molarity = 0.225 M
Number of mole of KI = 0.935mole
Volume =?
Molarity = mole / Volume
Volume = mole /Molarity
Volume = 0.935/0.225
Volume = 4.16L
Therefore, 4.16L of KI is needed.
Answer:
The answer is "Option b and Option c".
Explanation:
This buffer is a buffer of ammonia and ammonium ion. Thus it requires the solution
.
In point 1:
The solution containing
at 1M concentration would be given by mixing the two solutions. Thus, this buffer is a legitimate route.
In point 2:
It gives the ions you want but they are not the same.
In point 3:
and 
volume would not produce the same
concentrations. Therefore, this buffer isn't a valid route.
In point 4:
Some
volume and half
. This offers the same rate as half.