Answer:
The solubility of MnS will decrease on addition of KOH solution.
Explanation:
As per the equation given:
On dissolution of MnS in water it gives a basic solution as it gives hydroxide ions.
Now when the we are adding aqueous KOH solution, it will dissociate as:
Thus it will further furnish more hydroxide ion,
This will increase the concentration of hydroxide ions (present of product side), the system will try to decrease its concentration by shifting towards reactant side.
Thus the solubility of MnS will decrease on addition of KOH solution.
Answer:
just answer this and you will have yours
Explanation:Find the area of a circle with a diameter of \color{green}{16}16start color green, 16, end color green.
Either enter an exact answer in terms of \piπpi or use 3.143.143, point, 14 for \piπpi and enter your answer as a decimal.
Answer:
Mass released = 8.6 g
Explanation:
Given data:
Initial number of moles nitrogen= 0.950 mol
Initial volume = 25.5 L
Final mass of nitrogen released = ?
Final volume = 17.3 L
Solution:
Formula:
V₁/n₁ = V₂/n₂
25.5 L / 0.950 mol = 17.3 L/n₂
n₂ = 17.3 L× 0.950 mol/25.5 L
n₂ = 16.435 L.mol /25.5 L
n₂ = 0.644 mol
Initial mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.950 mol × 28 g/mol
Mass = 26.6 g
Final mass of nitrogen:
Mass = number of moles × molar mass
Mass = 0.644 mol × 28 g/mol
Mass = 18.0 g
Mass released = initial mass - final mass
Mass released = 26.6 g - 18.0 g
Mass released = 8.6 g
Answer: A) Bent or angular, polar
Explanation:
The central atom oxygen has two lone pairs and two bond pairs in 
. The number of electron pairs are 4, that means the hybridization will be 
and the electronic geometry of the molecule will be tetrahedral. But as there are two lone pair of atoms around the central oxygen atom, repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be bent shape.
The compound is polar as the net dipole moment of oxygen - fluoride bonds do not cancel each other out.
Answer:
Forward direction
Explanation:
The reaction quotient of an equilibrium reaction measures relative amounts of the products and the reactants present during the course of the reaction at particular point in the time.
Q < Kc , reaction will proceed in forward direction.
Q > Kc , reaction will proceed in backward direction.
Q = Kc , reaction at equilibrium.
It is the ratio of the concentration of the products and the reactants each raised to their stoichiometric coefficients. The concentration of the liquid and the gaseous species does not change and thus is not written in the expression.
Thus, for the reaction:
The expression is:
![Q=\frac {[CIO_3^{-}][Cl^{-}]^2}{[CIO^{-}]^3}](https://tex.z-dn.net/?f=Q%3D%5Cfrac%20%7B%5BCIO_3%5E%7B-%7D%5D%5BCl%5E%7B-%7D%5D%5E2%7D%7B%5BCIO%5E%7B-%7D%5D%5E3%7D)
Given,
[Cl⁻] = 0.50 mol/L; [ClO₃⁻] = 0.32 mol/L; [ClO⁻] = 0.24 mol/L
So,
Q = 5.7870
Since, Q < Kc (
)
The reaction will go in forward direction.
