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Arte-miy333 [17]
2 years ago
13

When a sample of oxygen gas in a closed container of constant volume is heated until its absolute temperature is doubled, which

of the following is also doubled?
a. density
b. pressure
c. average velocity
d. number of molecules
e. potential energy
Chemistry
1 answer:
saul85 [17]2 years ago
7 0

Answer: b. pressure

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure of gas  = p

P_2 = final pressure of gas  = ?

T_1 = initial temperature of gas  = t

T_2 = final temperature of gas = 2t

\frac{p}{t}=\frac{P_2}{2t}

P_2=2p

Thus the pressure also doubles when absolute temperature is doubled.

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Bella wants to know which mode of transportation is the fastest for getting from her home to the grocery store. She cans drive h
MrRissso [65]

Is this multiple choice? Is there any educational problem that really needs to be solved?

If you ask me I think a helicopter would be fastest, just sayin.


7 0
2 years ago
Calculate the hydrogen ion concentration in a solution of fruit juice having a pH of 4.25.
Airida [17]

Answer:

<h3>The answer is option B</h3>

Explanation:

The pH of a solution can be found by using the formula

pH = - log [ H+ ]

To find the hydrogen ion concentration substitute the pH into the above formula and solve for the [ H+ ]

From the question

pH = 4.25

So we have

4.25 = - log [ H+ ]

<u>Find the antilog of both sides</u>

That's

<h3>[ H+ ] =  {10}^{ - 4.25}</h3>

We have the final answer as

<h2>[ H+ ] = 5.6 \times  {10}^{ - 5}  \: M</h2>

Hope this helps you

3 0
1 year ago
En un balneario necesitan calentarse 1 millón de litros de agua anuales, subiendo la temperatura desde 15 ºC a 50 ºC y para ello
MAXImum [283]

Answer:

a) m_{CH_4}=2630kg

b) 1657 €

Explanation:

Hola,

a) En este problema, vamos a considerar el millón de litros de agua anuales, ya que con ellos podemos calcular el calor requerido para dicho calentamiento, sabiendo que la densidad del agua es de 1 kg/L:

Q_{H_2O}=m_{H_2O}Cp(T_2-T_1)=1x10^6LH_2O*\frac{1kgH_2O}{1LH_2O}*4.18\frac{kJ}{kg\°C}(50-15) \°C\\Q_{H_2O}=146.3x10^6kJ

Luego, usamos la entalpía de combustión del metano para calcular su requerimiento en kilogramos, sabiendo que la energía ganada por el agua, es perdida por el metano:

Q_{H_2O}=-Q_{CH_4}=-146.3x10^5kJ=m_{CH_4}\Delta _cH_{CH_4}

m_{CH_4}= \frac{Q_{CH_4}}{\Delta _cH_{CH_4}} =\frac{-146.3x10^5kJ}{-890kJ/molCH_4} *\frac{16gCH_4}{1molCH_4} \\\\m_{CH_4}=2630112.36g=2630kg

b) En este caso, consideramos que a condiciones normales de 1 bar y 273 K, 1 metro cúbico de metano cuesta 0,45 €, con esto, calculamos las moles de metano a dichas condiciones:

n_{CH_4}=\frac{PV}{RT}=\frac{1atm*1000L}{0.082\frac{atm*L}{mol*K}*273K} =44.67mol

Con ello, los kilogramos de metano que cuestan 0,45 €:

44.67molCH_4*\frac{16gCH_4}{1molCH_4}*\frac{1kg}{1000g} =0.715kgCH_4

Luego, aplicamos la regla de tres:

0.715 kg ⇒ 0.45 €

2630 kg ⇒ X

X = (2630 kg x 0.45 €) / 0.715 kg

X = 1657 €

Regards.

3 0
2 years ago
Gold has always been a highly prized metal, and it has been widely used from the beginning of history as a store of value. It do
Greeley [361]

Answer: The balanced equation is

Au(s) + 3HNO3(aq) + 4HCl(aq) ---> HAuCl4(aq) + 3NO2(g) +3H2O(l)

The function of HCl in a solution of Aqua regia, that is used to dissolve gold is to dissolve other metals like quartz or iron stone that surround the gold.

Explanation: To balance the equation, we check the ratio of each element in the reacting side and the product side ( left and right hand side). Let their ratio be equal be adding moles to the compound of the element or the element it's self in either side of the equation.

HCl which is called hydrochloric acid, is an acid that does not react with gold, but it react with every other substance, like your skin, metals etc. it is used to clean a gold, by dipping the gold inside it, all the metals on the surface of the gold will dissolve.

When dissolving a gold in aqua regia solution, HCL is added to prepare this solution because it will help to dissolve all other substance on the surface of the gold.

8 0
1 year ago
How many sodium ions are in the initial 50.00-mL solution of Na2CO3
tresset_1 [31]
From other sources, the given mass of the solute that is being dissolved here is 7.15 g Na2CO3 - 10H2O. We use this amount to convert it to moles of Na2CO3 by converting it to moles using the molar mass then relating the ratio of the unhydrated salt with the number of water molecules. And by the dissociation of the unhydrated salt in the solution, we can calculate the moles of Na+ ions that are present in the solution.

Na2CO3 = 2Na+ + CO3^2-

7.15 g Na2CO3 - 10H2O (1 mol / 402.9319 g) (1 mol Na2CO3 / 1 mol Na2CO3 - 10H2O) ( 1 mol Na2CO3 / 1 mol Na2CO3-10H2O ) ( 2 mol Na+ / 1 mol Na2CO3) = 0.04 mol Na+ ions present
8 0
2 years ago
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