All categories

2 years ago

A sample of copper with a mass of 63.5g contains 6.02 x10^23 atoms calculate the mass of an average copper atom

Chemistry

1 answer:

m_a_m_a [10]2 years ago

5 0

Answer:

The mass of an average copper atom is $1.0548\times 10^{-22}\ g$

Explanation:

Given:

The total mass of copper atoms, $m = 63.5\ g$

Number of atoms, $N=6.02\times 10^{23}$

Now, we are asked to find the mass of 1 copper atom.

We use unitary method to find the mass of 1 copper atom.

Mass of $N$ atoms = m

∴ Mass of 1 atom = $\frac{m}{N}$

Plug in 63.5 for 'm', $6.02\times 10^{23}$ for 'N' and simply.

Mass of 1 atom = $\dfrac{63.5}{6.02\times 10^{23}}=1.0548\times 10^{-22}\ g$

Therefore, the mass of an average copper atom is $1.0548\times 10^{-22}\ g$

You might be interested in

Determine the normality of the following solutions note the species of interest is H 95 g of PO4 3- in 100mL solution

Aliun [14]

Answer : The normality of the solution is, 30.006 N

Explanation :

Normality : It is defined as the number of gram equivalent of solute present in one liter of the solution.

Mathematical expression of normality is:

$\text{Normality}=\frac{\text{Gram equivalent of solute}}{\text{Volume of solution in liter}}$

or,

$\text{Normality}=\frac{\text{Weight of solute}}{\text{Equivalent weight of solute}\times \text{Volume of solution in liter}}$

First we have to calculate the equivalent weight of solute.

Molar mass of solute $PO_4^{3-}$ = 94.97 g/mole

$\text{Equivalent weight of solute}=\frac{\text{Molar mass of solute}}{\text{charge of the ion}}=\frac{94.97}{3}=31.66g.eq$

Now we have to calculate the normality of solution.

$\text{Normality}=\frac{95g}{31.66g.eq\times 0.1L}=30.006eq/L$

Therefore, the normality of the solution is, 30.006 N

5 0

2 years ago

After passing through pyruvate dehydrogenase and the citric acid cycle, one mole of pyruvate will result in the formation of ___

mamaluj [8]

Answer:

The answer to be filled in the respective blanks in question is

3 and 1

Explanation:

So, we know that the formation of cabon-dioxide mole and that of Adenosin-Tri-Phosphate (ATP) moles will be in the ratio of 3:1 i.e., three carbon-di-oxide moles and 1 ATP mole.

Therefore, we can say that one pyruvate mole when passed through citric acid cycle and pyruvate dehydrogenase yields carbon-di-oxide and ATP moles in the ratio 3:1

7 0

2 years ago

What vitamin a compounds bind with opsin to form rhodopsin??

irina [24]

The organic compound retinal binds with opsin and forms rhodopsin. Retinal is part of the molecule that is responsible for its color. This part is called chromophore. On the other hand, opsins are the proteins in photoreceptor cells. Retinal bounds with these opsins and forms rhodopsin: the basis of the human vision. Rhodopsin is also a protein.It is the pigment in the retinas of humans and animals.

7 0

2 years ago

Nitrogen gas can be prepared by passing gaseous ammonia over solid copper (II) oxide at high temperatures. If 18.1 g of Nh3 is r

Scilla [17]

I first converted the given grams of the reactants into moles, and then divided the moles by the coefficients in front of each of the reactant. The result with the smallest value will be the limiting reactant, and the value of CuO was the smallest, so it's the limiting reactant.

After figuring out which reactant is the limiting one, I took their given grams and converted it into moles, the divided it by the ratio of N2 to CuO (it's in the equation) to obtain the moles of N2, and then multiply it with the molar mass of N2 to get its mass in grams.

6 0

2 years ago

The diagram shows the scales used for recording temperatures. The labels for the scales are missing. 3 thermometers are oriented

QveST [7]

Answer d

Explanation:

8 0

2 years ago

Read 2 more answers