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1 year ago

Of the concentration units below, only ________ uses kg of solvent in its calculation.

Chemistry

1 answer:

oksano4ka [1.4K]1 year ago

6 0

Answer:

E) molality

Explanation:

Molality -

Molarity of a substance , is the number of moles present in a Kg of solvent .

Hence , the formula for molality is given as follow -

m = n / s

m = molality

s = mass of solvent in Kg ,

n = moles of solute ,

Hence , from the given information of the question,

The concentration unit which have Kg of solvent , is molality.

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The answer is it breaks down food into energy
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Approximately what volume do 3.0 moles of kr gas occupy at stp? 80.0 40.0 l none of the above 20.0

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None of the above.
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Problem Page A chemist measures the amount of bromine liquid produced during an experiment. He finds that of bromine liquid is p

masha68 [24]

The question is incomplete, here is the complete question:

A chemist measures the amount of bromine liquid produced during an experiment. She finds that 766.g of bromine liquid is produced. Calculate the number of moles of bromine liquid produced. Round your answer to 3 significant digits.

<u>Answer:</u> The amount of liquid bromine produced is 4.79 moles.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of liquid bromine = 766. g

Molar mass of liquid bromine, $(Br_2)$ = 159.8 g/mol

Putting values in above equation, we get:

$\text{Moles of liquid bromine}=\frac{766.g}{159.8g/mol}=4.79mol$

Hence, the amount of liquid bromine produced is 4.79 moles.

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1 year ago

The laser in a 3D printer uses light with a frequency of 3.844 × 1014 Hz. Calculate the wavelength of this light in nm. Show all

Natali5045456 [20]

Answer:

The wavelength of this light is 780.4 nm.

Explanation:

Given that,

The frequency of laser light, $f=3.844 \times 10^{14}\ Hz$

We need to find the wavelength of this light.

We know that,

$c=f\lambda$

Where

$\lambda$ is the wavelength of light

So,

$\lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3\times 10^8}{3.844 \times 10^{14}}\\\\=7.804\times 10^{-7}\ m\\\\=780.4\ nm$

So, the wavelength of this light is 780.4 nm.

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1 year ago

2Na2O2 + 2CO2 → 2Na2CO3 + O2

ahrayia [7]

the actual yield is the amount of Na₂CO₃ formed after carrying out the experiment

theoretical yield is the amount of Na₂CO₃ that is expected to be formed from the calculations

we need to first find the theoretical yield

2Na₂O₂ + 2CO₂ ---> 2Na₂CO₃ + O₂

molar ratio of Na₂O₂ to Na₂CO₃ is 2:2

number of Na₂O₂ moles reacted is equal to the number of Na₂CO₃ moles formed

number of Na₂O₂ moles reacted is - 7.80 g / 78 g/mol = 0.10 mol

therefore number of Na₂CO₃ moles formed is - 0.10 mol

mass of Na₂CO₃ expected to be formed is - 0.10 mol x 106 g/mol = 10.6 g

therefore theoretical yield is 10.6 g

percent yield = actual yield / theoretical yield x 100%

81.0 % = actual yield / 10.6 g x 100 %

actual yield = 10.6 x 0.81

actual yield = 8.59 g

therefore actual yield is 8.59 g

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