The value of X is 10 hence the formula of unknown hydrate sodium sulfate is NaSO4.10 H20
calculation
step 1:find the moles of NaSO4 and the moles of H2O
moles= mass/molar mass
moles of Na2SO4=1.42÷142=0.01 moles
moles of H20= mass of H2O/molar mass of H2O
mass of H2O= 3.22-1.42=1.8g
mole of H2O is therefore 1.8÷18=0.1 moles
step 2: find the mole ratio by dividing each mole by smallest number of mole (0.01)
that is Na2So4= 0.01/0.01 =1
H2O= 0.1/0.01=10
Answer:
<h3>The answer is option B</h3>
Explanation:
The pH of a solution can be found by using the formula
pH = - log [ H+ ]
To find the hydrogen ion concentration substitute the pH into the above formula and solve for the [ H+ ]
From the question
pH = 4.25
So we have
4.25 = - log [ H+ ]
<u>Find the antilog of both sides</u>
That's
<h3>
![[ H+ ] = {10}^{ - 4.25}](https://tex.z-dn.net/?f=%5B%20H%2B%20%5D%20%3D%20%20%7B10%7D%5E%7B%20-%204.25%7D%20)
</h3>
We have the final answer as
<h2>
![[ H+ ] = 5.6 \times {10}^{ - 5} \: M](https://tex.z-dn.net/?f=%5B%20H%2B%20%5D%20%3D%205.6%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20%20%5C%3A%20M)
</h2>
Hope this helps you
Answer:
The answer to be filled in the respective blanks in question is
3 and 1
Explanation:
So, we know that the formation of cabon-dioxide mole and that of Adenosin-Tri-Phosphate (ATP) moles will be in the ratio of 3:1 i.e., three carbon-di-oxide moles and 1 ATP mole.
Therefore, we can say that one pyruvate mole when passed through citric acid cycle and pyruvate dehydrogenase yields carbon-di-oxide and ATP moles in the ratio 3:1
Answer:
3-methylthiophene > thiophene > benzene > 2-methylfuran
Explanation:
Primarily, five membered heterocyclic aromatic rings undergo nitration at carbon-2. This is because, nitration at carbon-2 leads to the formation of three resonance structures while attack at carbon-3 yields only two resonance structures, hence it is less stabilized.
The presence of a methyl group which donates electrons promotes the stabilization of the cation formed in the nitration of 3-methylthiophene.
2-methylfuran is the least reactive towards nitration because the 2-position has been blocked by a methyl group.