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2 years ago

Balance the equation xcl2(aq)+agno3(aq)=x(no3)2(aq)+agcl(s)

Chemistry

2 answers:

Fittoniya [83]2 years ago

8 0

Answer:

XCl2(aq) + 2AgNO3(aq) --------> X(NO3)2(aq) + 2AgCl(s)

Explanation:

The rule guiding he balancing of reaction equations is that the number of atoms of each element on both sides of the reaction equation must be the same.

In order to balance this equation, this rule must be applied. The balanced reaction equation therefore becomes;

XCl2(aq) + 2AgNO3(aq) --------> X(NO3)2(aq) + 2AgCl(s)

We can see by conducting an atom count that the number of atoms of each element on both sides of reaction equation is the same hence the equation is balanced.

lisabon 2012 [21]2 years ago

6 0

Explanation:

$XCl _{2(aq)} + 2AgNO _{3(aq)}→X(NO _{3}) _{2(aq)} +2 AgCl _{(s)}$

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calculate the water potential of a solution of 0.15m sucrose. the solution is at standard temperature.

Mrac [35]

Answer:

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

Explanation:

Water potential = Pressure potential + solute potential

$P_w=P_p+P_s$

$P_w=P_p+(-iCRT)$

We have :

C = 0.15 M, T = 273.15 K

i = 1

The water potential of a solution of 0.15 m sucrose= $P_w$

$P_p=0 bar$ (At standard temperature)

$P_s=-iCRT=-\times 1\times 8.314\times 10^{-2}bar L/mol K\times 273.15 K=-3.406 bar$

$P_w=0 bar+(-3.406 ) bar$

The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.

7 0

2 years ago

Suppose that a certain fortunate person has a net worth of $79.0 billion ($7.90×1010). If her stock has a good year and gains $3

mario62 [17]

A net worth: $79.0 billion.
Value of stock : $3.20 billion.
New net worth:
$79.0 + $3.20 = $82.20 billion = $82.20 * 10^9 = $8.20 * 10^10

7 0

2 years ago

When 0.40 mol Al is mixed with 0.40 mol Br2, the following reaction occurs: 2Al(s) + 3Br2(l) → 2AlBr3(s) Identify the limiting r

Lera25 [3.4K]

Answer:

d. The limiting reactant is Br2, and 0.13 mol Al should remain unreacted.

Explanation:

From the reaction, 2Al(s) + 3Br2(l) → 2AlBr3(s)

2 moles of Al combines with 3 moles of Br to form 2 moles of AlBr3

Hence 1 mole of Br combines with 2/3 moles of Al

or 0.4 moles of Br combines with 2/3×0.4 moles of Al or 0.267 Moles of Al leaving

0.4 - 0.267 = 0.133 moles of Al remaining unreacted

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2 years ago

Large sharks eat many other marine life animals. The sharks and the animals they eat are all part of which level of organization

Sladkaya [172]

Answer:

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8 0

2 years ago

Read 2 more answers

A 25.0-ml sample of hno3 solution requires 35.7 ml of 0.108 m na2co3 to completely react with all of the hno3 in the solution. w

Rasek [7]

If we write the equation of the reaction that will take place, it is:
2HNO₃ + Na₂CO₃ → 2NaNO₃ + H₂CO3

The molar ratio of 2HNO₃ : Na₂CO₃ = 1 : 2
Therefore, we can set up the equation:
M₁V₁ = 2M₂V₂
Where the left side of the equation has the molarity and volume of HNO₃ and the right side has the molarity and concentration of Na₂CO₃. Substituting:
M₁ = (2 x 0.108 x 35.7) / 25
M₁ = 0.308 M

5 0

2 years ago