The first ionization energy, e, of a potassium atom is 0.696 aj. what is the wavelength of light, in nm, that is just sufficient
1 answer:
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Answer:
.
Explanation:
<h3>Step One: calculate the coefficients. </h3>Look up the relative atomic mass of these four elements on a modern periodic table:
: approximately
.
: approximately
.
: approximately
.
: approximately
.
The relative atomic mass of an element is numerically equal to the mass (in grams, ,) of one mole of atoms of this element.
For example, the relative atomic mass of is approximately
. Therefore, each mole of
atoms would have a mass of
.
This sample contains of carbon. That would correspond to approximately
of
atoms.
Similarly, for the other three elements:
.
.
.
Hence, the ratio between these elements in this compound would be:
.
In the empirical formula of a compound, the coefficients should represent the smallest possible integer ratio between the number of atoms of these elements.
is indeed the smallest possible integer ratio between the number of atoms of these elements.
Apply the Hill System to arrange these four elements in the empirical formula. In the Hill System:
If carbon, , is present in this compound, then:
- The other elements in this compound will be listed in alphabetical order.
If there is no carbon in this compound, then list all the elements in this compound in alphabetical order.
Both (carbon) and
(hydrogen) are found in this compound. Therefore, the first element in the list would be
. The second would be
, followed by
and then
.
Hence, the empirical formula of this compound would be .