answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Verizon [17]
2 years ago
14

Which statement below correctly identifies the number of subatomic particles inside and outside the nucleus of an argon atom?

Chemistry
1 answer:
Juliette [100K]2 years ago
6 0

Answer:

A

Explanation:

You might be interested in
If a 300.0 ml sample of a gas is heated at constant pressure from 25.0ºc to 55.0ºc, its new volume is _____ ml?
jekas [21]

 The new  volume is    330.2 ml


<u><em>calculation</em></u>

 The new  volume is  calculated using  the Charles  law formula

that is  V1/T1= V2/T2

where T1= 25.0  c  into kelvin  =  25 +273  = 298 K

         V1=  300.0 ml

       T2  = 55.0  c  into kelvin = 273   +55  =328  K

      V2 =  ? ml


make V2  the   subject of the formula  by  multiplying  both side by T2

V2= V1T2/ T1

V2 =[ (300.0 ml x 328 k)  / 298 k}  = 330.2 ml


8 0
2 years ago
A 0.3870-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.7191Â g of co
olchik [2.2K]
The chemical formula for the compound can be written as,

    CxHyOz 

where x is the number of C atoms, y is the number of H atoms, and z is the number of O atoms. The combustion reaction for this compound is,
   
    CxHyOz + O2 --> CO2 + H2O 

number of moles of C:
     (0.7191 g)(1 mol CO2/44 g of CO2) = 0.0163 mol CO2
 This signifies that 0.0163 mole of C and the mass of carbon in the compound,
        (0.0163 mols C)(12 g C/ 1 mol C) = 0.196 g C

number of moles H:
      (0.1472 g H2O)(1 mol H2O/18 g H2O) = 0.00818 mol H2O

This signifies that there are 0.01635 atoms of H in the compound.
      mass of H in the compound = (0.01635 mols H)(1 g of H) = 0.01635 g H

Mass of oxygen in the compound,
   0.3870 - (0.196 g C + 0.01635 g H) = 0.1746 g

Moles O in the compound = (0.1746 g O)(1 mol O/16 g O) = 0.0109 mols O

The formula of the compound is,
      C0.0163H0.01635O0.0109

Dividing the numbers by the least number,
    C3/2H3/2O

The empirical formula of the compound is therefore,
    <em>  C₃H₃O₂</em>
5 0
2 years ago
A(n) _______________ can be formed by linking together several monosaccharides via glycosidic bonds.
mario62 [17]

Answer:

A polysaccharide (n) can be formed by linking several monosaccharides through glycosidic linkages.

Explanation:

Polysaccharides are carbohydrates or complex carbohydrates, where monosaccharides join with glucosidic bonds to form a more complex structure that would be the polysaccharide.

An example of a polysaccharide is starch, or glycogen.

Starch is found in many foods such as potatoes or rice, and glycogen is a form of energy reserve of our organism housed in muscles and liver to fulfill locomotion, physical activity, and other activities that consist of glycolysis.

Polysaccharides are degraded in our body by different stages, and several enzymes unlike monosoccharides or disaccharides, since they have more unions and a more complex structure to disarm in our body and thus assimilate it.

Polysaccharides are also part of animal structures, such as insect shells or nutritional sources, among others.

7 0
2 years ago
Calculate the ratio of effusion rates of cl2 to f2 .
Lelechka [254]
<span>Answer: Graham's law of gaseous effusion states that the rate of effusion goes by the inverse root of the gas' molar mass. râšM = constant Therefore for two gases the ratio rates is given by: r1 / r2 = âš(M2 / M1) For Cl2 and F2: r(Cl2) / r(F2) = âš{(37.9968)/(70.906)} = 0.732 (to 3.s.f.)</span>
4 0
2 years ago
What is the formal charge on the nitrogen in hydroxylamine, h2noh?
andrew11 [14]
<h3>Answer:</h3>

             Formal Charge on Nitrogen is "Zero".

<h3>Explanation:</h3>

Formal Charge on an atom in molecules is calculated using following formula;

Formal Charge  =  [# of Valence e⁻s] - [e⁻s in lone pairs + 1/2 # of Bonding e⁻s]

As shown in attached picture of Hydroxylamine, Nitrogen atom is containing two electrons in one lone pair of electrons and six electrons in three single bonds with two hydrogen and one oxygen atom respectively.

Hence,

                                  Formal Charge  =  [5] - [2 + 6/2]

                                  Formal Charge  =  [5] - [2 + 3]

                                  Formal Charge  =  5 - 5

                                  Formal Charge  =  0    (zero)

Hence, the formal charge on nitrogen atom in hydroxylamine is zero.

5 0
2 years ago
Other questions:
  • Identify the phrases that generally apply to molecular compounds a contain metals and nonmetals
    12·2 answers
  • Which expression is equal to the number of grams (g) in 2.43 kilograms (kg)?
    14·2 answers
  • An element with the electron configuration [xe] 6s24f145d7 would belong to which class on the periodic table?
    14·1 answer
  • In looking at the bolded atoms in the answer choices, which pair consists of molecules having the same geometry? view available
    15·1 answer
  • If a runners power is 400 w as she runs, how much chemical energy dose she convert into other forms in 10.0 minuets?
    13·1 answer
  • The elements X and Y combine in different ratios to form four different types of compounds: XY, XY2, XY3, and XY4. Consider that
    15·1 answer
  • Acetaldehyde shows two UV bands, one with a lmax of 289 nm ( 5 12) and one with a lmax of 182 nm ( 5 10,000). Which is the n p*
    5·1 answer
  • Which substance can not be broken down by a
    12·1 answer
  • When small pieces of manganese oxide were added to a solution of hydrogen peroxide, water and oxygen were produced. Manganese ox
    13·1 answer
  • The electron configuration of an element is shown below. 1s22s22p5 Name the group this element belongs to in the periodic table
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!