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lyudmila [28]
2 years ago
11

If the same amount of heat is supplied to samples of 10.0 g each of aluminum, iron, and copper all at 15.0 °c, which sample woul

d reach the highest temperature
Chemistry
1 answer:
lozanna [386]2 years ago
6 0

The specific heat of aluminum, iron and copper is 0.897 J/g °C, 0.452 J/g °C and 0.385 J/g °C respectively.

The formula that relates specific heat capacity and change in temperature is as follows:

E=m×c×ΔT

Here, E is heat, m is mass, c is specific heat and ΔT is change in temperature.

On rearranging,

c=\frac{E}{m\times \Delta T}

Thus, change in temperature is inversely proportional to change in temperature. Change in temperature will be more for the element with low value of specific heat which is Cu in this case.

Since, the initial temperature is same for all the samples thus, Cu will reach the highest  temperature.

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The average kinetic energy of water molecules is greatest in which of these samples?(1) 10 g of water at 35°C(2) 10 g of water a
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The question asks about the average kinetic energy so it is not related with mass. We only need to compare the temperature. The higher temperature is, the higher kinetic energy is. So the answer is (2).
3 0
1 year ago
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What mass of copper is required to replace silver from 4.00g of silver nitrate dissolved in water?
larisa [96]
The balanced chemical reaction is written as:

<span>Cu +2AgNO3 → Cu(NO3)2 + 2Ag
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We are given the amount of silver nitrate to be used for the reaction. This value will be the starting point of our calculations. It is as follows:

4.00 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Cu / 2 mol AgNO3 ) ( 63.456 g / 1 mol ) = 0.747 g Cu
3 0
1 year ago
A balloon filled with air has a volume of 4.24 liters at 23.00°
meriva

The  new volume  if the balloon is cooled at constant pressure  is  3.98 L


 <u><em>Explanation</em></u>

The new  volume is calculated using the Charles law formula

that is V1/ T1 = V2/T2  where,

V1 = 4.24 l

T1= 23c  into kelvin = 23  +273 =296 K

T2 = 5.00 c into kelvin = 5.00 + 273 = 278 K

V2 = ?


by making  V2 subject the subject of the formula  by multiplying both side by T2

V2 = V1 xT2/ T1

V2 =  (4.24 L   x 278 K)  / 296 k  =3.98 L



6 0
1 year ago
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What volume (mL) of a 0.3428 M HCl(aq) solution is required to completely neutralize 23.55 mL of a 0.2350 M Ba(OH)2(aq) solution
EastWind [94]

Answer:

The volume required for complete neutralize is 32.29 mL

Explanation:

The computation of the volume required for complete neutralize is shown below:

As we know that, the balanced equation is

Ba(OH)_2 + 2Hcl\rightarrow Bacl_2 + 2H_2O

Now

The number of moles of Ba(OH)_2 = n_1 = 1

And, the number of moles of Hcl = n_2 = 2

Therefore

The equation i.e. to be used to find out the volume is given below:

\frac{M_1V_1}{n_1} =  \frac{M_2V_2}{n_2}

V_2 = \frac{M_1V_1}{n_1} \times \frac{n_2}{M_2} \\\\ = \frac{0.2350 \times 23.55}{1} \times \frac{2}{0.3428} \\\\ = \frac{11.0685}{0.3428}

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6 0
2 years ago
A container contains a mixture of hydrogen, oxygen and nitrogen gases. The pressure of hydrogen is 78 kPa. The pressure of oxyge
Nuetrik [128]

<u>Answer:</u> The total pressure of the container is 140.2416 kPa

<u>Explanation:</u>

Dalton's law of partial pressure states that the total pressure of the system is equal to the sum of partial pressure of each component present in it.

To calculate the total pressure, we use the law given by Dalton, which is:

P_T=p_{H_2}+p_{O_2}+p_{N_2}

We are given:

Vapor pressure of hydrogen gas, p_{H_2} = 78 kPa

Vapor pressure of oxygen gas, p_{O_2} = 2.4416 kPa

Vapor pressure of nitrogen gas, p_{N_2} = 59.8 kPa

Putting values in above equation, we get:

P_T=78+2.4416+59.8\\\\P_T=140.2416kPa

Hence, the total pressure of the container is 140.2416 kPa

7 0
1 year ago
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