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2 years ago

How many grams are in 3.3 moles of potassium sulfide , k2s

1 answer:

7 0

In 3.3 moles of potassium sulphide (K2S), there are 363.99 g. Let's first calculate the molar mass of K2S (Mr) which is the sum of atomic masses (Ar) of its elements. According to the periodic table, Ar(K) = 39.1 g/mol and Ar(S) = 32.1 g/mol. Mr(K2S) = 2Ar(K) + Ar(S) = 2 * 39.1 + 32.1 = 110.3 g/mol. Thus, there are 110.3 g per 1 mol. There will be x grams in 3.3 moles. 110.3 g : 1 mol = x : 3.3 mol. x = 110.3 g * 3.3 mol : 1 mol = 363.99 g.

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A tank of 0.1m3 volume contains air at 25∘C and 101.33 kPa. The tank is connected to a compressed-air line which supplies air at

Dmitriy789 [7]

Answer:

Amount of Energy = 23,467.9278J

Explanation:

Given

Cv = 5/2R

Cp = 7/2R wjere R = Boltzmann constant = 8.314

The energy balance in the tank is given as

∆U = Q + W

According to the first law of thermodynamics

In the question, it can be observed that the volume of the reactor is unaltered

So, dV = W = 0.

The Internal energy to keep the tank's constant temperature is given as

∆U = Cv((45°C) - (25°C))

∆U = Cv((45 + 273) - (25 + 273))

∆U = Cv(20)

∆U = 5/2 * 8.314 * 20

∆U = 415.7 J/mol

Before calculating the heat loss of the tank, we must first calculate the amount of moles of gas that entered the tank where P1 = 101.33 kPa

The Initial mole is calculated as

(P * V)/(R * T)

Where P = P1 = 101.33kPa = 101330Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

So, n = (101330 * 0.1)/(8.314*298)

n = 4.089891232222

n = 4.089

Then we Calculate the final moles at P2 = 1500kPa = 1500000Pa

V = Volume of Tank = 0.1m³

R = 8.314J/molK

T = Initial Temperature = 25 + 273 = 298K

n = (1500000 * 0.1)/(8.314*298)

n = 60.54314465936812

n = 60.543

So, tue moles that entered the tank is ∆n

∆n = 60.543 - 4.089

∆n = 56.454

Amount of Energy is then calculated as:(∆n)(U)

Q = 415.7 * 56.454

Q = 23,467.9278J

3 0

2 years ago

Dry ice is solid carbon dioxide. A 0.050-g sample of dry ice is placed in an evacuated 4.6-L vessel at 30 °C. Calculate the pres

goldenfox [79]

The answer is 6.1*10^-3 atm.

The pictures and explanations are there.

3 0

2 years ago

N2 and H2 are mixed in 14:3 mass ratio. After certain time ammonia was found to be 40% by mol. The mole fraction of N2 at that t

son4ous [18]

Answer : The mole fraction of nitrogen will be 0.4615.

Explanation : When nitrogen ( $N_{2}$ )and hydrogen ( $H_{2}$ )are mixed, the mole ratio becomes 1 : 1.5,

Now we know that ( $H_{2}$ ) is acting as a limiting agent.

So at the time of when 0.4 moles of ( $NH_{3}$ ) is been formed it requires 0.4 moles of ( $N_{2}$ ) and 3.4 moles of ( $H_{2}$ )

So, we find the the remaining ( $N_{2}$ ) will be 0.6 and

( $H_{2}$ ) will be 0.3 mole present in mixture.

So, the mole fraction of ( $N_{2}$ ) becomes = 0.6 / (0.6 + 0.4 + 0.3) Which becomes = 0.4615

8 0

2 years ago

Read 2 more answers

Write chemical equations and corresponding equilibrium expressions for each of the two ionization steps of carbonic acid. Part A

lesantik [10]

Answer: The chemical equations and equilibrium constant expression for each ionization steps is written below.

Explanation:

The chemical formula of carbonic acid is $H_2CO_3$ . It is a diprotic weak acid which means that it will release two hydrogen ions when dissolved in water

The chemical equation for the first dissociation of carbonic acid follows:

$H_2CO_3(aq.)\rightleftharpoons H^+(aq.)+HCO_3^-(aq.)$

The expression of first equilibrium constant equation follows:

$Ka_1=\frac{[H^+][HCO_3^{-}]}{[H_2CO_3]}$

The chemical equation for the second dissociation of carbonic acid follows:

$HCO_3^-(aq.)\rightarrow H^+(aq.)+CO_3^{2-}(aq.)$

The expression of second equilibrium constant equation follows:

$Ka_2=\frac{[H^+][CO_3^{2-}]}{[HCO_3^-]}$

Hence, the chemical equations and equilibrium constant expression for each ionization steps is written above.

6 0

2 years ago

Determine the number of neutrons in an atom of Rg-272.

IRISSAK [1]

In order to find the number of neutrons in the atom,

you need to calculate the difference between the top and bottom numbers

which means 272 - 111 = 161

Hope this helps

6 0

2 years ago