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coldgirl [10]
2 years ago
11

The farming methods promoted by the California Ricelands Habitat Partnership are best described as beneficial to both farmers an

d wetland species because _______.
Chemistry
1 answer:
kiruha [24]2 years ago
6 0

Answer:The farming methods promoted by the California Ricelands Habitat Partnership are best described as beneficial to both farmers and wetland species because California Rice Commission and individual growers to further enhance the habitat [ value of California’s rice fields to waterbirds. This collective approach creates synergy for fully realizing the wildlife values in California rice

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Marie discovers boxes of elements in a storage room. The boxes do not say which elements they contain, but they do have informat
Mazyrski [523]
<span>The elements in a Periodic Table are grouped according to their classifications. The major classifications are Metals, Non-metals, and Metalloids. Their level of reactivity can be gauged by simply looking at their position in the table. For Metals, their reactivity increases as you move to the left then going down. Non-metal reactivity increases as you move to the right then going up, starting at the bottom of the table.</span>
5 0
2 years ago
Read 2 more answers
A student carries out the precipitation reaction shown below, starting with 0.030 moles of calcium nitrate. The final mass of th
valkas [14]

Answer:

a. Ca₃(PO₄)₂.

b. 0.010 moles of Ca₃(PO₄)₂ can we expect to be produced

c. 3.1g of Ca₃(PO₄)₂

d. Percent yield = 93.5%

Explanation:

a. Based on the reaction:

3Ca(NO₃)₂(aq) + 2Na₃PO₄(aq) → Ca₃(PO₄)₂(s) + 6NaNO₃(aq)

<em>3 moles of calcium nitrate reacts with 2 moles of sodium phosphate producieng 1 mole of calcium phosphate.</em>

<em />

As you can see, Ca₃(PO₄)₂ is a solid product -(s)-, that means when the reaction occurs the precipitate produced is the solid,

<h3>Ca₃(PO₄)₂</h3><h3 />

b. As 3 moles of calcium nitrate produce 1 mole of calcium phosphate and there are 0.030 moles of calcium nitrate

0.030 moles Ca(NO₃)₂ × (1 mol Ca₃(PO₄)₂ / 3 moles Ca(NO₃)₂) =

<h3>0.010 moles of Ca₃(PO₄)₂ can we expect to be produced</h3><h3 />

c. As molar mass of Ca₃(PO₄)₂ is 310.18g/mol, the mass of 0.010 moles (The expected mass) is;

0.010 moles Ca₃(PO₄)₂ × (310.18g / mol) =

<h3>3.1g of Ca₃(PO₄)₂</h3><h3 />

d. The percent yield is defined as 100 times the ratio between the obtained yield (That is 2.9g of precipitate, Ca₃(PO₄)₂) and the expected yield, 3.1g of Ca₃(PO₄)₂:

\frac{2.9g}{3.1g} *100

<h3>Percent yield = 93.5%</h3>
7 0
2 years ago
This same chemistry student has a weight of 155 lbs. What is the student’s weight in
Virty [35]

Answer:

the same chemistry student has a weight of 155lbs what is the student weight in grams? (16 oz= 1 lb, 1 oz= 28.34g)

Explanation:1 lb = 16oz, so multiply your pounds by 16 to get you ounces of the student, then multiply by 28.34 to get grams

155 X 16 X 28.34 = 70283.2

8 0
1 year ago
Read 2 more answers
A chemical reaction is done in the setup shown , resulting in a change of mass. What will happen if the same reaction is done in
irina1246 [14]
<h2>Answer:</h2>

The mass of the system will remain the same if there is no conversion of mass to energy in the reaction.

<h3>Explanation:</h3>
  • If the system is closed, then according to the law of mass conservation the mass of the reaction system will remain the same.
  • <u><em>Law of conservation of the mass: In simple words, it is described as the mass of a closed system can never be changed, it may transfer from one form to another or change into energy.</em></u>
  • But if the reaction involves energy transfer like heat or light production, in this case, the mass can be changed.
5 0
2 years ago
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A solution contains cr3+ ions. the addition of 0.063 l of 1.50 m naf solution was needed to completely precipitate the chromium
steposvetlana [31]

Cr{3+} + 3 NaF → CrF3 + 3 Na{+} <span>

First calculate the total mols of NaF. 

(0.063 L) x (1.50 mol/L NaF) = 0.0945 mol NaF total </span>

 

Using stoichiometric ratio:

<span>0.0945 mol NaF * (1 mol Cr3+ / 3 mol NaF) * (51.9961 g Cr3+/mol) = 1.6379 g Cr3+</span>
6 0
2 years ago
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