Answer:
ΔH=15000
J = 15KJ
Explanation:
In this exercise you have find the enthalpy of reaction this is the difference between enthalpy of reactans and products,
For the following equation
H2A(aq) + 2 BOH(aq) → B2A(aq) + 2 H2O(l)
We know that 0.20 moles of BOH reacted with excess amount of H2A solution and 1500. J
so,
(2mol/0,2mol)*1500J=15000J
for de reactions exothermics tha enthalpy is negative so:
ΔH=15000
J = 15KJ
The new volume if the balloon is cooled at constant pressure is 3.98 L
<u><em>Explanation</em></u>
The new volume is calculated using the Charles law formula
that is V1/ T1 = V2/T2 where,
V1 = 4.24 l
T1= 23c into kelvin = 23 +273 =296 K
T2 = 5.00 c into kelvin = 5.00 + 273 = 278 K
V2 = ?
by making V2 subject the subject of the formula by multiplying both side by T2
V2 = V1 xT2/ T1
V2 = (4.24 L x 278 K) / 296 k =3.98 L
Answer: Lead(II) nitrate but idk the rest
Explanation:
When solving for the mass of a compound when you’re given the number of moles present, you need to know the molar mass (how many grams there are in a mole of that compound).
In this case, we can make the following equation:
3.00(14.01 + 2(16.00))
In Nitrogen, the molar mass is 14.01 grams per mole, and Oxygen is 16.01 grams per mole.
However, because there are 2 oxygen atoms present per molecule, you must multiply it by two in order to solve for the molar mass.
Anyway:
3.00(14.01 + 2(16.00))
Simplify:
3.00(14.01 + 32.00)
3.00(46.01)
Multiply:
3.00(46.01) = 138.03
3.00 moles of NO2 has a mass of 138.03 grams.
-T.B.
