Question

Two electrons in an atom are separated by 1.5 ✕ 10-10 m, the typical size of an atom. what is the electric force between them?

Answer 1

Answer:The electric force between them is $1.024\times 10^{-17} N$.

Explanation:

Charge on an electron = $q_1=q_2=-1.6\times 10^{-19} C$

Distance between the two electrons = $r=1.5\times 10^{-10} m$

The Electric force between two electrons is given by :

$F_e=k\times \frac{q_1\times q_2}{r^2}$

$F_e=9\times 10^9 N m^2/C^2\times \frac{-1.6\times 10^{-19} C\times -1.6\times 10^{-19} C}{(1.5\times 10^{-10} m)^2}=1.024\times 10^{-17} N$

The electric force between them is $1.024\times 10^{-17} N$.

Answer 2

Given two electrons with charge of 1.5x10^-10 m 

The electostatic force between them is determined by this formula: 

F = kq1q2/r^2
   
where 

k = 9x10^9
q1 = q2 = 1.5x10^-10
r = 2.82x10^-15

F = 9x10^9 * (1.5x10^-10)^2 / 2.82x10^-15
   = 71808.51