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2 years ago

Mass in grams of 6.25 mol of copper (II) nitrate?

2 answers:

8 0

Cu = 63.546
N= 14.001 g/mol
O= 15.999 g/mol * 3 = 47.997

Copper (II) Nitrate has a MW of 125.544 g/mol

6.25 x 125.544

= 784.65 <--- is your answer, if there were was a multiple choice or not :)

Margaret [11]2 years ago

3 0

Answer:

Mass of 6.25 moles of copper(II) nitrate = 1025 grams

Explanation:

Let us calculate the molar mass of Copper (II) nitrate

Molecular formula = Ca(NO₃)₂

Atomic mass of Ca = 40 g/mol

Atomic mass of N =14 g/mol

Atomic mass of O = 16 g/mol

molar mass of Ca(NO₃)₂ = 40 + (14 X2) +( 6X16) = 164 g/mol

$moles=\frac{mass}{molarmass}$

therefore

mass = moles X molar mass

mass = 6.25 X 164 = 1025 grams

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110.8 ºC

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To solve this problem we will make use of the Clausius-Clayperon equation:

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Now we have to assume that ΔHºvap remains constant which is a good asumption given the narrow range of temperatures in the data ( 104-125) ºC

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377 0.002653 5.9915

384 0.002604 6.2115

390 0.002564 6.3969

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Perhaps that is the reason the question was flagged.

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