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Setler [38]
2 years ago
10

a student adds 15 g of baking soda to 10 g of acetic acid in a beaker. a chemical reaction occurs and a gas is given off. after

the reaction, the mass of the remaining in beaker is 23 g. has mass been converserved in the reaction? explain.
Chemistry
1 answer:
Zanzabum2 years ago
7 0

The chemical equation representing the reaction between baking soda and acetic acid :

NaHCO_{3}(aq)+CH_{3}COOH(aq)-->CH_{3}COONa(aq)+H_{2}O(l)+CO_{2}(g)

According to the Law of conservation of mass, the overall mass is conserved in a chemical reaction. That is total mass of reactants is equal to the mass of the products.

Given here Mass of Baking soda = 15 g

Mass of acetic acid = 10 g

Total mass of the reactants = 15 g +10 g = 25 g

After the reaction, total mass of products = 23 g

This difference in masses must be because one of product carbon dioxide is a gas, which is lost and hence the mass of products is lower than the mass of reactants. Therefore, the mass is conserved in this reaction.

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Explanation:

The observation of student was that thermometer reading changed from 27°C to 35°C which indicates that temperature of the beaker solution rose after reaction due to release of heat during reaction as a product.

Those chemical reactions which gives heat energy as a product into their surrounding are categorized as exothermic reactions. During the course of these reaction temperature of the surroundings also increased.

So, this means that reaction between silver nitrate and copper wire is an exothermic reaction.

Three ways that the student could speed up the reaction :

  • By adding catalyst to the reaction.
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2 years ago
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How many sigma and pi bonds in propionic bond
Ierofanga [76]
Propanoic acid formula is ch ch 2 so it has 8 bonds
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2 years ago
Water at 4.4°C is to flow through a horizontal, commercial steel pipe having a length of 305 m at the rate of 150 gal/min. If a
Pavel [41]

Answer:

d = 70.5 mm

Explanation:

given,

length of pipe = 305 m

discharge rate = 150 gal/min

pipe diameter = ?

1 gal/min = 6.30902 ×  10⁻⁵ m³/s

150 gal/min = 150 × 6.30902 ×  10⁻⁵ m³/s

                   = 9.46 × 10⁻³ m³/s

h = \dfrac{flv^2}{2gd}

h = \dfrac{flv^2}{2gd}

Q = A V

h = \dfrac{fl(\dfrac{Q}{A})^2}{2gd}

h = \dfrac{fl(\dfrac{Q}{\dfrac{\pi}{4}d^2})^2}{2gd}

h= \dfrac{8flQ^2}{\pi^2gd^5}

f = 0.048 from moody chart using P/D = 0.00015

\dfrac{1}{d^5}= \dfrac{6.1\times \pi^2\times 9.8}{8\times 0.048\times 305\times 0.00946^2}

d = 70.5 mm

Diameter of the pipe is equal to 70.5 mm

7 0
2 years ago
Calculate the first and second velocities of the car with one washer attached to the pulley, using the formulas v1 = 0.25 m / t1
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Answer: .11  .28

Explanation:

I was on this lesson

8 0
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7.744 Liters of nitrogen are contained in a container. Convert this amount to grams.
Xelga [282]

Answer:

9.69g

Explanation:

To obtain the desired result, first let us calculate the number of mole of N2 in 7.744L of the gas.

1mole of a gas occupies 22.4L at stp.

Therefore, Xmol of nitrogen gas(N2) will occupy 7.744L i.e

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Now let us convert 0.346 mole of N2 to gram in order to obtain the desired result. This is illustrated below:

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Mass of N2 =?

Mass = number of mole x molar Mass

Mass of N2 = 0.346 x 28

Mass of N2 = 9.69g

Therefore, 7.744L of N2 contains 9.69g of N2

7 0
2 years ago
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