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dexar [7]
1 year ago
8

b) Write a few paragraphs describing the chemical reaction and explaining the energy change in the reaction. Your document shoul

d: i. identify the reactants and products. ii. describe the change in energy that occurs as bonds are broken and formed. iii. identify how the potential energy of the reactants compares to the potential energy of the products. iv. state and explain the net change in enthalpy. v. identify whether the reaction is endothermic or exothermic. vi. explain how energy is conserved between the reaction and the surrounding environment.
Chemistry
2 answers:
Lena [83]1 year ago
5 0

Answer:

The energy change in a chemical reaction is due to the difference in the amounts of stored chemical energy between the products and the reactants. This stored chemical energy, or heat content, of the system is known as its enthalpy.

Explanation:

if u want to u can give me the crown btw have a good day

Maksim231197 [3]1 year ago
3 0

Answer:

here is what i put for this project:

The reaction in this project is exothermic. The energy change in a chemical reaction is due to the difference in the amounts of stored chemical energy between the products and the reactants. This stored chemical energy, or heat content, of the system is known as its enthalpy. The potential energy in reactants is higher than the potential energy of products in an exothermic reaction. Since energy is given off, the products are lower in energy than the reactants. The energy that is given off is a result of the formation of new bonds.

The change of the enthalpy happening in the chemical reaction is different from the pathway in between the initial and the final states. The addition of the equation gives the net change of the enthalpy. Enthalpy change is the amount of heat evolved or absorbed in the reaction under constant pressure. This can be calculated by checking the amount of heat evolved during the reaction. This reaction occurs at a constant pressure.

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Potassium carbonate, K2CO3, sodium iodide, NaI, potassium bromide, KBr, methanol, CH3OH, and ammonium chloride, NH4Cl, are solub
just olya [345]

Answer:

A. K₂CO₃

Explanation:

The chemical reaction showing the ions produced on dissolving Potassium carbonate in water is:

K₂CO₃ ⇒ 2K⁺ + CO₃²⁻

Number of ions produced = 2 + 1 = 3

The chemical reaction showing the ions produced on dissolving sodium iodide in water is:

NaI ⇒ Na⁺ + I⁻

Number of ions produced = 1 + 1 = 2

The chemical reaction showing the ions produced on dissolving potassium bromide in water is:

KBr ⇒ K⁺ + Br⁻

Number of ions produced = 1 + 1 = 2

The chemical reaction showing the ions produced on dissolving ammonium chloride in water is:

NH₄Cl ⇒ NH₄⁺ + Cl⁻

Number of ions produced = 1 + 1 = 2

<u>The largest number of dissolved particles per mole of dissolved solute is produced by Potassium carbonate.</u>

5 0
2 years ago
Marisa is a 120 pound female who attended a party where alcohol was being served. She began drinking at 9 pm. After finishing he
tiny-mole [99]

Answer:

Explanation:

hour that passes and she drank for 3 hours so .045% must be subtracted. .20% - .045 % = .155%2) Obviously drunk, staggering, irrational behavior, no coordination 3) Yes, she is driving intoxicated because Texas’ legal limit is .08% and she is above that. Scenario 2 4) David drank 6 drinks. At 240 lbs, he is at .10%. However, subtracting .060% (.015% per hour x 4 hours) gives a BAC of .04%5) Relaxed, mellow, may show slight signs of impairment 6) David is okay to drive at .04% according to Texas law. However, the effects of alcohol can vary greatly for many reasons. 7) Even though Anthony drank the same amount during the same amount of time, several factors could cause Anthony’s BAC to be higher than David’s, thus making him “more drunk.”

4 0
2 years ago
How many moles of hydrogen are needed to produce 13.78 mol of ethane?
mamaluj [8]
Ethane is an alkane. Methane is also an alkane and is considered to be the simplest alkane. The difference is ethane has only 2 carbon. That carbon has 6 hydrogen attached to it. So what we do is we multiply the moles of ethane by the number of hydrogen (by dimension analysis) resulting to 82.68 moles H.
4 0
2 years ago
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What volume of a 0.716 m kbr solution is needed to provide 30.5 g of kbr?
Jlenok [28]
Answer is: volume of KBr is 357 mL.
c(KBr) = 0,716 M = 0,716 mol/L.
m(KBr) = 30,5 g.
n(KBr) = m(KBr) ÷ M(KBr).
n(KBr) = 30,5 g ÷ 119 g/mol.
n(KBr) = 0,256 mol.
V(KBr) = n(KBr) ÷ c(KBr).
V(KBr) = 0,256 mol ÷ 0,716 mol/L.
V(KBr) = 0,357 L · 1000 mL/L = 357 mL.
7 0
2 years ago
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Which of the compounds above are strong enough acids to react almost completely with a hydroxide ion (pka of h2o = 15.74) or wit
luda_lava [24]

The compounds can react with OH⁻ and HCO₃⁻ only C₅H₆N pyridinium

<h3><em>Further explanation </em></h3>

In an acid-base reaction, it can be determined whether or not a reaction occurs by knowing the value of pKa or Ka from acid and conjugate acid (acid from the reaction)

Acids and bases according to Bronsted-Lowry

Acid = donor (donor) proton (H + ion)

Base = proton (receiver) acceptor (H + ion)

If the acid gives (H +), then the remaining acid is a conjugate base because it accepts protons. Conversely, if a base receives (H +), then the base formed can release protons and is called the conjugate acid from the original base.

From this, it can be seen whether the acid in the product can give its proton to a base (or acid which has a lower Ka value) so that the reaction can go to the right to produce the product.

The step that needs to be done is to know the pKa value of the two acids (one on the left side and one on the right side of the arrow), then just determine the value of the equilibrium constant

Can be formulated:

K acid-base reaction = Ka acid on the left : K acid on the right.

or:

pK = acid pKa on the left - pKa acid on the right

K = equilibrium constant for acid-base reactions

pK = -log K;

K~=~10^{-pK}

K value> 1 indicates the reaction can take place, or the position of equilibrium to the right.

There is some data that we need to complete from the problem above, which is the pKa value of some compounds that will react, namely:

pyridinium pKa = 5.25

acetone pKa = 19.3

butan-2-one pKa = 19

Let's look at the K value of each possible reaction:

pka H₂O = 15.74, pka of H₂CO₃ = 6.37)

  • 1. C₅H₆N pyridinium

* with OH⁻

C₅H₆N + OH- ---> C₅H₅N- + H₂O

pK = pKa pyridinium - pKa H₂O

pK = 5.25 - 15.74

pK = -10.49

K~=~10^{4.9}

K values> 1 indicate the reaction can take place

* with HCO3⁻

C₅H₆N + HCO₃⁻-- ---> C₅H₅N⁻ + H₂CO₃

pK = 5.25 - 6.37

pK = -1.12

K`=~10^{1.12]

Reaction can take place

  • 2. Acetone C₃H₆O

* with OH-

C₃H₆O + OH⁻ ---> C₃H₅O- + H₂O

pK = 19.3 - 15.74

pK = 3.56

K~=~10^{ -3.56}

Reaction does not happen

* with HCO₃-

C₃H₆O + HCO₃⁻ ----> C₃H₅O⁻ + H₂CO₃

pK = 19.3 - 6.37

pK = 12.93

K`=~10 ^{-12.93}

Reaction does not happen

  • 3. butan-2-one C₄H₇O

* with OH-

C₄H₇O + OH- ---> C₄H₆O- + H₂O

pK = 19 - 15.74

pK = 3.26

K~=~10^{-3.26}

Reaction does not happen

* with HCO₃⁻

C₄H₇O + HCO₃⁻ ---> C₄H₆O⁻ + H₂CO₃

pK = 19 - 6.37

pK = 12.63

K~=~ 10^{-12.63}

Reaction does not happen

So that can react with OH⁻ and HCO₃⁻ only C₅H₆N pyridinium

<h3><em>Learn more </em></h3>

the lowest ph

brainly.com/question/9875355

the concentrations at equilibrium.

brainly.com/question/8918040

the ph of a solution

brainly.com/question/9560687

Keywords : acid base reaction, the equilibrium constant

5 0
2 years ago
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