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2 years ago

20 PTS!!! What is the volume of a gas at 90.0°C, if it occupies 1.41 L at 170°C?

Chemistry

2 answers:

Fofino [41]2 years ago

5 0

Answer:

The new volume of the gas is 1.72L

Explanation:

V1 = 1.41L

V2 = ?

T1 = 90°C = (90+273.15)K = 363.15K

T2 = 170°C =(170+273.15)K = 443.15K

To find the new volume V2 of the gas, we apply Charles law which states that the volume of a fixed mass of gas is directly proportional to its temperature provided that pressure remains constant.

V = KT, K = V1 / T1 = V2 /T2 = V3 /T3.......= Vn / Tn

V1 / T1 = V2 / T2

Solve for V2,

V2 = (V1 * T2) / T1

V2 = (1.41 * 443.15) / 363.15

V2 = 1.72L

The new volume of the gas is 1.72L

Margarita [4]2 years ago

3 0

Answer:

1.72 L

Explanation:

Initial Temperature of the gas T =90°+273= 363 K

Initial Volume of the gas V1= 1.41 L

Final temperature of the gas T2= 170°c +273= 443 K

Final volume of the gas V2= ????

Using Charles law;

V1/T1 = V2/T2

V1T2= V2T1

V2= V1T2/T1

V2= 1.41×443/363

V2= 1.72 L

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1 year ago

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Answer: All of the statements are true.

Explanation:

(a) Considering the system mentioned in the equation:-

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2 years ago

Silver chloride is formed by mixing silver nitrate and barium chloride solutions. What volume of 1.50 M barium chloride solution

konstantin123 [22]

Answer:

1.22 mL

Explanation:

Let's consider the following balanced reaction.

2 AgNO₃ + BaCl₂ ⇄ Ba(NO₃)₂ + 2 AgCl

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0.525 g × (1 mol/143.32 g) = 3.66 × 10⁻³ mol

The molar ratio of AgCl to BaCl₂ is 2:1. The moles of BaCl₂ are 1/2 × 3.66 × 10⁻³ mol = 1.83 × 10⁻³ mol.

The volume of 1.50 M barium chloride containing 1.83 × 10⁻³ moles is:

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1 year ago

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Answer:

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2 years ago

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kirza4 [7]

Answer:

See the explanation

Explanation:

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