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2 years ago

What other objects could be used to simulate radioactive and nonradioactive nuclei? Check all that apply.

Chemistry

1 answer:

Ray Of Light [21]2 years ago

3 0

Answer:

quarters

a computer that shows pictures of atoms on screen

candy with letters on one side

Explanation:

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How many atoms of oxygen are in 75.6g of silver nitrate (AgNO3)?

vodomira [7]

Answer:

1.50x10^21 molecules O2

Explanation:

8 0

2 years ago

In the figure shown, AD, CE, and FB intersect at point F.

EleoNora [17]

Answer:

you need to send us the figure

Explanation:

7 0

2 years ago

HELP ASAP!!!!!!

blondinia [14]

2, 4, 1

Explanation:

We have the following chemical reaction:

Ag₂O → Ag + O₂

To balance the chemical equation the number of atoms of each element entering the reaction have to be equal to the number of atoms of each element leaving the reaction, in order to conserve the mass.

So the balanced chemical equation is:

2 Ag₂O → 4 Ag + O₂

Learn more about:

balancing chemical equations

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6 0

2 years ago

Are carboxylic acids of more than 10 carbons more soluble in polar or nonpolar solvents? Explain.

lina2011 [118]

Answer: Non polar solvents

Explanation:

Since with increasing the size of alkyl group hydrophobic nature increases and solubility in polar solvents decreases .

Hence Carboxylic acids with more than 10 carbon atoms, solubility is more in non polar solvents.

8 0

2 years ago

2.92 A 50.0-g silver object and a 50.0-g gold object are both added

Trava [24]

Answer:

82.9 mL

Explanation:

1. Volume of silver

$\begin{array}{rcl}\text{Density}&=& \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho&=& \dfrac{m}{V}\\\\V &=& \dfrac{m}{\rho}\\\\& = & \dfrac{\text{50.0 g}}{\text{10.49 g$\cdot$mL}^{-1}}\\\\& = & \text{4.766 mL}\\\end{array}\\\text{The volume of the silver is $\large \boxed{\textbf{4.766 mL}}$}$

2. Volume of gold

$\begin{array}{rcl}V& = & \dfrac{\text{50.0 g}}{\text{19.30 g$\cdot$mL}^{-1}}\\\\& = & \text{2.591 mL}\\\end{array}\\\text{The volume of the gold is $\large \boxed{\textbf{2.591 mL}}$}$

3. Total volume of silver and gold

V = 4.766 mL + 2.591 mL = 7.36 mL

4 New reading of water level

V = 75.5 mL + 7.36 mL = 82.9 mL

3 0

2 years ago