<span>(CH3)2-CH2-C(F)(OH)-CH2-CBr2-CH3</span>
Answer : The enthalpy change for the reaction is, 201.9 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The balanced reaction of 
will be,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
(4) 
Now we will multiply the reaction 1 by 2, revere the reaction 2, reverse and half the reaction 3 and 4 then adding all the equations, we get :
(1) 
(2) 
(3) 
(4) 
The expression for enthalpy of the reaction will be,
Therefore, the enthalpy change for the reaction is, 201.9 kJ
excess hydrogen ions can break chemical bonds
, can change the shape of large complex molecules, rendering them nonfunctional and can disrupt tissue function.
Answer: Option (c) is the correct answer.
Explanation:
A water molecule is made up of two hydrogen atoms and one oxygen atom. Due to the difference in electronegativity of hydrogen and oxygen, the electrons are pulled more towards oxygen atom.
As a result, a partial positive charge will develop on hydrogen atom and a partial negative charge will develop on oxygen atom.
Thus, we can conclude that adjacent water molecules interact through the electrical attraction between the hydrogen of one water molecule and the oxygen of another water molecule.
Answer:
4 g after 58.2 years
0.0156 After 291 years
Explanation:
Given data:
Half-life of strontium-90 = 29.1 years
Initially present: 16g
mass present after 58.2 years =?
Mass present after 291 years =?
Solution:
Formula:
how much mass remains =1/ 2n (original mass) ……… (1)
Where “n” is the number of half lives
to find n
For 58.2 years
n = 58.2 years /29.1 years
n= 2
or 291 years
n = 291 years /29.1 years
n= 10
Put values in equation (1)
Mass after 58.2 years
mass remains =1/ 22 (16g)
mass remains =1/ 4 (16g)
mass remains = 4g
Mass after 58.2 years
mass remains =1/ 210 (16g)
mass remains =1/ 1024 (16g)
mass remains = 0.0156g
