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zhuklara [117]
2 years ago
9

A 0.100 m solution of which one of the following solutes will have the highest vapor pressure? A 0.100 m solution of which one o

f the following solutes will have the highest vapor pressure? KClO4 Ca(ClO4)2 NaCl sucrose Al(ClO4)3
Chemistry
1 answer:
Assoli18 [71]2 years ago
5 0

Explanation:

Vapor pressure is defined as the pressure exerted by vapors or gas on the surface of a liquid.

Vapor pressure is inversely proportional to the number of solute particles. Hence, more will be the solute particles lower will be the vapor pressure and vice-versa.

(a)   KClO_{4} \rightarrow K^{+} + ClO^{-}_{4}

It dissociates to give two particles.

(b)  Ca(ClO_{4})_{2} \rightarrow Ca^{2+} + 2ClO^{-}_{4}

Total number of particles it give upon dissociation are 1 + 2 = 3. Hence, it gives 3 particles.

(c)   Al(ClO_{4})_{3} \rightarrow Al^{3+} + 3ClO^{-}_{4}

Total number of particles it give upon dissociation are 1 + 3 = 4. Hence, it gives 4 particles.

(d)  Surcose being a cobvalent compound doe not dissociate into ions. Therefore, there will be only 1 particle is present.

(e)   NaCl \rightarrow Na^{+} + Cl^{-}

Total number of particles it give upon dissociation are 1 + 1 = 2. Hence, it gives 2 particles.

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Gaseous ICl (0.20 mol) was added to a 2.0 L flask and allowed to decompose at a high temperature:
Ne4ueva [31]

Answer:

The Kc is 1.36 (but this is not an option, may be the options are wrong, or may be I was .. Thanks!)

Explanation:

Let's think all the situation.

               2 ICl(g)   ⇄   I₂(g)    +    Cl₂(g)

Initially      0.20              -               -

Initially I have only 0.20 moles of reactant, and nothing of products. In the reaction, an x amount of compound has reacted.

React          x              x/2               x/2

Because the ratio is 2:1, in the reaction I have the half of moles.

So in equilibrium I will have

           (0.20 - x)          x/2             x/2

Notice that I have the concentration in equilibrium so:

0.20 - x = 0.060

x = 0.14

So in equilibrium I have formed 0.14/2 moles of I₂ and H₂ (0.07 moles)

Finally, we have to make, the expression for Kc and remember that must to be with concentration in M (mol/L).

As we have a volume of 2L, the values must be /2

Kc = ([I₂]/2 . [H₂]/2) / ([ICl]/2)²

Kc = (0.07/2 . 0.07/2) / (0.060/2)²

Kc = 1.225x10⁻³ / 9x10⁻⁴

Kc = 1.36

8 0
2 years ago
Which statements are true of the electron cloud model? Check all that apply. It is also known as the planetary model. It is cons
barxatty [35]

Answer:

-It is considered the modern atomic model.

-It describes the probable locations of the electrons

Explanation:

edge 2020

8 0
2 years ago
Read 2 more answers
A solution was prepared by mixing 50.0 g
frez [133]

Answer:

4.78 %.

Explanation:

<em>mass percent is the ratio of the mass of the solute to the mass of the solution multiplied by 100.</em>

<em></em>

<em>mass % = (mass of solute/mass of solution) x 100.</em>

<em></em>

mass of MgSO₄ = 50.0 g,

mass of water = d.V = (0.997 g/mL)(1000.0 mL) = 997.0 g.

mass of the solution = mass of water + mass of MgSO₄ = 997.0 g + 50.0 g = 1047.0 g.

<em>∴ mass % = (mass of solute/mass of solution) x 100</em> = (50.0 g/1047.0 g) x 100 = <em>4.776 % ≅ 4.78 %.</em>

4 0
2 years ago
consideras util conocer las propiedades extensivas e intensivas de los insumos utilizados para la elaboración de producto ¿por q
Brums [2.3K]

Answer:

Explanation:

No.

Las propiedades físicas de los materiales y sistemas a menudo se pueden clasificar como intensivas o extensivas, según cómo cambia la propiedad cuando cambia el tamaño (o extensión) del sistema. Según la IUPAC, una cantidad intensiva es aquella cuya magnitud es independiente del tamaño del sistema, mientras que una cantidad extensiva es aquella cuya magnitud es aditiva para los subsistemas. Esto refleja las ideas matemáticas correspondientes de media y medida, respectivamente.

Una propiedad intensiva es una propiedad a granel, lo que significa que es una propiedad física local de un sistema que no depende del tamaño del sistema o de la cantidad de material en el sistema. Los ejemplos de propiedades intensivas incluyen temperatura, T; índice de refracción, n; densidad, ρ; y dureza de un objeto.

Por el contrario, propiedades extensivas como la masa, el volumen y la entropía de los sistemas son aditivas para los subsistemas porque aumentan y disminuyen a medida que crecen y se reducen, respectivamente.  

Estas dos categorías no son exhaustivas, ya que algunas propiedades, físicas no son exclusivamente intensivas ni extensivas. Por ejemplo, la impedancia eléctrica de dos subsistemas es aditiva cuando, y solo cuando, se combinan en serie; mientras que si se combinan en paralelo, la impedancia resultante es menor que la de cualquiera de los subsistemas.

¡Espero haberte ayudado!  :)

7 0
2 years ago
Complete the following radioactive decay problem.<br> 210/84 Po --&gt; 206/82 Pb + ____/____ __
vazorg [7]

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + _2^4He  

Your equation is:  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + ?

It becomes easier to balance the equation if we replace the "?" with an element symbol _<em>x</em>^<em>y</em>Z.  

Then the equation becomes  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb +_<em>x</em>^<em>y</em>Z

The main point to remember in balancing nuclear equations is that the <em>sums of the superscripts and the subscripts</em> must be the same <em>on each side of the equation</em>.  

Sum of superscripts: 210 = 206 + <em>y</em>, so <em>y</em> =4.  

Sum of subscripts: 84 = 82 + <em>x</em>, so<em> x</em> = 2.

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + _2^4He

We should recall that _2^4He is an <em>α particl</em>e.

Thus, the equation represents the α decay of polonium-210 to lead-206.

The nuclear equation is  

₈₄²¹⁰Po ⟶ ₈₂²⁰⁶Pb + _2^4He

4 0
2 years ago
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