Answer:
Volume of water that must be added is 1.10 L
Explanation:
pH measures the acidity or the alkalinity of a substance
It is given by;
pH = -log[H+]
Using this we can find the concentration of H+ ions in the acid
pH = 2 = -log[H+]
Therefore;
[H+] = 10^-2
= 0.01 M
But, since 1 mole HNO₃ ionizes to give 1 mole of H+, then the concentration of HNO₃ is equal to the concentration of H+ ([HNO₃] = [H+])
Therefore;
Initial [HNO₃] = 0.01 M
Initial volume of HNO₃ = 11.1 mL or 0.0111 L
We can then use dilution equation to find the final volume after dilution.
The final pH is 4
Therefore, [H+] = 10^-4
= 0.0001 M
Thus, the final concentration of HNO₃ is 0.0001 M
Using dilution equation;
M1V1 =M2V2
Thus; V2 = M1V1÷ M2
= (0.01 M× 0.0111 L)÷ 0.0001 M
= 1.11 L
This means the final total volume will 1.11 L or 1110 ml
Therefore; The volume of water added = 1110 ml - 11.1 ml
= 1098.9 ml or
= 1.0989 L
= 1.10 L(2 d.p.)
Hence, The volume of water that must be added is 1.10 L
The pair which consist of molecules having the same geometry is CH2CCI2 and CH2CH2.
Both of these molecules contain double bonds, which has sp^2 hybridization and they possess a trigonal planar geometry. In trigonal planar geometry, the molecule consist of three equally spaced sp^2 hybrid orbitals, which arranged at angle 120 degree.
I believe the correct answer from the choices listed above is option B. The stair-step line between the pink squares and the yellow squares separates the metals <span>from the nonmetals. Hope this answers the question. Have a nice day.</span>
On temperature 25°C (298,15K) and pressure of 1 atm each gas has same amount of substance:
n(gas) = p·V ÷ R·T = 1 atm · 20L ÷ <span>0,082 L</span>·<span>atm/K</span>·<span>mol </span>· 298,15 K
n(gas) = 0,82 mol.
1) m(He) = 0,82 mol · 4 g/mol = 3,28 g.
d(He) = 10 g + 3,28 g ÷ 20 L = 0,664 g/L.
2) m(Ne) = 0,82 mol · 20,17 g/mol = 16,53 g.
d(Ne) = 26,53 g ÷ 20 L = 1,27 g/L.
3) m(CO) = 0,82 mol ·28 g/mol = 22,96 g.
d(CO) = 32,96 g ÷ 20L = 1,648 g/L.
4) m(NO) = 0,82 mol ·30 g/mol = 24,6 g.
d(NO) = 34,6 g ÷ 20 L = 1,73 g/L.
Answer:
Gd → Gd⁺ + 1e⁻, Gd⁺ → Gd⁺² + 1e⁻, Gd⁺² → Gd⁺³ + 1e⁻
Explanation:
The ionization energy is the energy necessary to remove one electron of the atom, transforming it in a cation. The first ionization energy is the energy necessary to remove the first electron, the second energy, to remove the second electron, and then successively.
Thus, for gadolinium (Gd)
Fisrt ionization:
Gd → Gd⁺ + 1e⁻
Second ionization:
Gd⁺ → Gd⁺² + 1e⁻
Third ionization:
Gd⁺² → Gd⁺³ + 1e⁻
