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Sindrei [870]
2 years ago
10

Write equations that show the processes that describe the first, second, and third ionization energies for a gaseous gadolinium

atom. Express your answers as chemical equations separated by commas.
Chemistry
1 answer:
Anastaziya [24]2 years ago
3 0

Answer:

Gd → Gd⁺ + 1e⁻, Gd⁺ → Gd⁺² + 1e⁻, Gd⁺² → Gd⁺³ + 1e⁻

Explanation:

The ionization energy is the energy necessary to remove one electron of the atom, transforming it in a cation. The first ionization energy is the energy necessary to remove the first electron, the second energy, to remove the second electron, and then successively.

Thus, for gadolinium (Gd)

Fisrt ionization:

Gd → Gd⁺ + 1e⁻

Second ionization:

Gd⁺ → Gd⁺² + 1e⁻

Third ionization:

Gd⁺² → Gd⁺³ + 1e⁻

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Answer:

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6 0
2 years ago
How many moles of lithium are present in a sample that contains 2.45x10^87 formula units of Li2SO4?​
ddd [48]

The answer is: 8.14·10⁶³ moles of lithium are present.

N(Li₂SO₄) = 2.45·10⁸⁷; number of formula units of lithium sulfate.

n(Li₂SO₄) = N(Li₂SO₄) ÷ Na.

n(Li₂SO₄) = 2.45·10⁸⁷ ÷ 6.022·10²³ 1/mol.

n(Li₂SO₄) = 4.07·10⁶³ mol; amount of lithium sulfate

In one molecule of lithium sulfate, there are two atoms of lithium.

n(Li₂SO₄) : n(Li) = 1 : 2.

n(Li) = 2 · 4.07·10⁶³ mol.

n(Li) = 8.14·10⁶³ mol; amount of lithium atoms.

3 0
2 years ago
Propose a plausible mechanism for the reaction f2 + 2clo2 → 2fclo2 given that the rate law for the reaction is rate = k[f2][clo2
shepuryov [24]

<u>The given reaction is:</u>

F2 + ClO2 → 2FClO2

Rate = k[F2][ClO2]

<u>Explanation:</u>

The possible mechanism for this reaction can be broken down into two steps with the slow step being the rate determining step

Step 1:       F2 + ClO2 → FClO2 + F ----------- Slow

Step 2:      F + ClO2 → FClO2           ----------- Fast

-----------------------------------------------------------

Overall:  F2 + 2ClO2 → 2FClO2

Rate = k[F2][ClO2]

 


8 0
1 year ago
Read 2 more answers
When acids react with water, ions are released which then combine with water molecules to form .
mestny [16]
When acids react with water, H ions are released which then combine with water molecules to form H₃O⁺
7 0
2 years ago
Read 2 more answers
Which aqueous solution would exhibit a lower freezing point, 0.35 m k2so4 or 0.50 m kcl? explain and show necessary calculations
Umnica [9.8K]
Answer is: a lower freezing point has solution of K₂SO₄.

Change in freezing point from pure solvent to solution: ΔT =i · Kf · b.<span>
Kf - molal freezing-point depression constant for water is 1.86°C/m.
b -  molality, moles of solute per kilogram of solvent.
i - </span>Van't Hoff factor.<span>
b(K</span>₂SO₄<span>) = 0.35 m.
</span>b(KCl) = 0.5 m.
i(K₂SO₄) = 3.
i(KCl) = 2.
ΔT(K₂SO₄) = 3 · 0.35 m · 1.86°C/m.
ΔT(K₂SO₄) = 1.953°C.
ΔT(KCl) = 2 · 0.5 m · 1.86°C/m.
ΔT(KCl) = 1.86°C.


8 0
2 years ago
Read 2 more answers
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