MNaHCO₃: 23+1+12+(48×3) = 84g
mCH₃COOH: 12+(1×3)+12+(16×2)+1 = 60g
.................
84g NaHCO₃ react with 60g CH₃COOH
83g NaHCO₃ react with...........
84g ----- 60g
83g ----- X
X = 59,29g CH₃COOH
We used 70g CH₃COOH, it' too much.
So, acetic acid is excess reagent, and sodium bicarbonate is limiting reagent.
_______________________________
B) Amount of CH3COOH is in excess.
:•)
Energy, in a form of gamma rays, is <span>released when an electron and its antiparticle (positron) annihilate each other. </span>
Answer:
3.69 g
Explanation:
Given that:
The mass m = 325 g
The change in temperature ΔT = ( 1540 - 165)° C
= 1375 ° C
Heat capacity
= 0.490 J/g°C
The amount of heat required:
q = mcΔT
q = 325 × 0.490 × 1375
q = 218968.75 J
q = 218.97 kJ
The equation for the reaction is expressed as:

Then,
1 mole of the ethyne is equal to 26 g of ethyne required for 1544 kJ heat.
Thus, for 218.97 kJ, the amount of ethyne gas required will be:

= 3.69 g
Answer:
The mass of sodium that reacted is 230 grams
Explanation:
The balance equation of the reaction is first written .
sodium = Na
Chlorine = Cl2
sodium chloride = NaCl
2Na + Cl2 → 2NaCl
from the balance equation we calculate the molar mass involve in the reaction
Molar mass of sodium from the equation = 23(2) = 46 g
molar mass of sodium chloride from the eqaution = 23 × 2 + 35.5 × 2 = 46 + 71 = 117 g
If 46g of sodium is in 117 g of sodium chloride
? gram will be in 585 g of sodium chloride
cross multiply
46 × 585/117 = 26910/117 = 230 g
The mass of sodium that reacted is 230 grams
Answer is: A. Chemical energy to electromagnetic energy and thermal energy.
Balanced chemical reaction: 2Mg(s) + O₂(g) → 2MgO(s) + energy.
This is chemical change (chemical reaction), because new substance (magnesium oxide MgO) is formed, the atoms are rearranged and the reaction is followed by an energy change (exothermic reaction because energy is released).
Chemical changes (chemical synthesis) is when a substance combines with another (in this example magnesium and oxygen) to form a new substance.