Answer:1
Explanation:i know cuz I got it right
The liquid would be equivalent to the cytoplasm and the particles would be equivalent to organelles.
Answer:
2.65 M
Explanation:
Convert grams of K₂CO₃ to moles. The molar mass is 138.205 g/mol.
(110 g)/(138.205 g/mol) = 0.796 mol
Convert milliliters of solution to liters.
300 mL = 0.300 L
Divide moles of K₂CO₃ by liters of solution.
0.796 mol/0.300 L = 2.65 mol/L = 0.265 M
Answer:
Explanation:
Hello,
On the attached document, you will find the procedure regarding the required volume. At first, it is necessary to know atoms by day produced, by using a rule of three. Subsequently, we compute the moles per day and finally the volume via the ideal gas equation at STP.
Best regards.
First we need to find the number of moles of both K and O reacted
K - 0.779 g / 39 g/mol
= 0.02 mol
the mass of O₂ reacted = 1.417 g - 0.779 g = 0.638 g
O₂ moles = 0.638 g / 32 g/mol
= 0.02 mol
the number of both K and O₂ moles reacted are equal
therefore stoichiometry of K to O₂ reacted are 1:1
then the formula of potassium superoxide is KO₂
