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Ganezh [65]
2 years ago
12

Cathy’s favorite salad dressing is a liquid with particles of salt, pepper, and garlic. When comparing a spoonful of salad dress

ing to a cell, what would the liquid be equivalent to? What would the particles be equivalent to? The liquid would be equivalent to cytoplasm or oil or water .The particles would be equivalent to objects or organelles organs
Chemistry
2 answers:
Alchen [17]2 years ago
8 0

Answer:

The liquid is proportional to cytoplasm and the particles would be proportional to organelles.

Explanation:

The cytoplasm in cell biology refers to all the substances inside a cell, enveloped by the cell membrane. The majority of the activities in the cell occurs inside the cytoplasm. The cytoplasm comprises about 80 percent of water and is generally transparent.  

On the other hand, a tiny cellular composition, which does unique activities inside a cell is known as an organelle. The organelles are enclosed inside the cytoplasm of both prokaryotic and eukaryotic cells.  

SCORPION-xisa [38]2 years ago
4 0
The liquid would be equivalent to the cytoplasm and the particles would be equivalent to organelles. 
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How many moles of hydrogen gas are produced when 0.066 mole of sodium is completely reacted?
SVEN [57.7K]
Base on my research the complete reaction of hydrogen and sodium are form by this equation  2Na + 2H2O = 2NaOH +H2 If we base from this equation it shows you already the ratio of the moles of the product and reactants taking part in the reaction

1 mole of Na r/w 1 mole of water to produce .5 mole of Hydrogen 

Therefore, .066 mole of Na produces .033 moles of H2
6 0
2 years ago
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For scuba dives below 150 ft, helium is often used to replace nitrogen in the scuba tank. If 15.2 g of He(g) and 30.6 g of O2(g)
abruzzese [7]

Answer:

see explanation below

Explanation:

To do this exercise, we need to use the following expression:

P = nRT/V

This is the equation for an ideal gas. so, we have the temperature of 22 °C, R is the gas constant which is 0.082 L atm / mol K, V is the volume in this case, 5 L, and n is the moles, which we do not have, but we can calculate it.

For the case of the oxygen (AW = 16 g/mol):

n = 30.6 / 32 = 0.956 moles

For the case of helium (AW = 4 g/mol)_

n = 15.2 / 4 = 3.8 moles

Now that we have the moles, let's calculate the pressures:

P1 = 0.956 * 0.082 * 295 / 5

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P2 = 3.8 * 0.082 * 295 / 5

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Finally the total pressure:

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7 0
2 years ago
How many grams of calcium cyanide (Ca(CN)2) are contained in 0.79 mol of calcium cyanide?
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I dont know but do you know da wae brudda?


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2 years ago
A pharmacist–herbalist mixed 100 g lots o St. John’s wort containing the ollowing percentages o the active component hypericin:
Anna [14]

Answer:

strength of hypericin in mixture = 0.42 %

Explanation:

given data

each lot = 100 g

active component hypericin = 0.3%, 0.7%, and 0.25%

solution

we get here percent strength o hypericin in the mixture that is

Hypericin contribution lot 1 =  \frac{0.3}{100} × 100

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and

Hypericin contribution lot 2 = \frac{0.3}{100} × 100

Hypericin contribution lot 2 = 0.7 g

and

Hypericin contribution lot 3 = \frac{0.25}{100} × 100  

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so

total 300 g mixture of hypericin contain = 0.3 g + 0.7 g + 0.25 g

total 300 g mixture of hypericin = 1.25 g  

so here percent strength o hypericin in mixture is

strength of hypericin in mixture = \frac{1.25}{300} × 100  

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5 0
1 year ago
Convert 1.3902 hectoliters to centiliters.
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<span>The answer is 13,902 centiliters.

</span>
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