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2 years ago

If 110. grams of potassium carbonate (K2CO3) is dissolved into 300. mL of solution, what is the molarity of the solution?

Chemistry

2 answers:

Ivan2 years ago

7 0

Answer:

2.7 M

Explanation:

M=moles of solute/volume of solution (L)

First, you need to calculate the number of moles using the given mass and the molar mass.

110 g138.205 g/mol=0.80 mol

Then, you can solve for molarity using the molarity equation.

M=0.80 mol0.300 L=2.7 M

Remember, you need to convert mL to L before you can calculate molarity.

il63 [147K]2 years ago

6 0

Answer:

2.65 M

Explanation:

Convert grams of K₂CO₃ to moles. The molar mass is 138.205 g/mol.

(110 g)/(138.205 g/mol) = 0.796 mol

Convert milliliters of solution to liters.

300 mL = 0.300 L

Divide moles of K₂CO₃ by liters of solution.

0.796 mol/0.300 L = 2.65 mol/L = 0.265 M

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Which equation shows the proper setup to find the volume of a 0.250 M CaCl2 solution that contains 39.5 g of CaCl2?

Jlenok [28]

Molarity = number of mole of substance(n) / volume of solution (V).

n(CaCl2) = mass (CaCl2)/M(CaCl2)

M(CaCl2) = 40+2*35.5 = 111 g/mol

n(CaCl2) =39.5 g CaCl2*1 mol/111g

0.250 M = 39.5 g CaCl2*1 mol/111g*volume of solution (V).

volume of solution (V) = 39.5 g CaCl2*1 mol/(0.250 M*111g) = 1.42 L

4 0

2 years ago

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g When 2.50 g of methane (CH4) burns in oxygen, 125 kJ of heat is produced. What is the enthalpy of combustion (in kJ) per mole

Anna [14]

Answer:

-800 kJ/mol

Explanation:

To solve the problem, we have to express the enthalpy of combustion (ΔHc) in kJ per mole (kJ/mol).

First, we have to calculate the moles of methane (CH₄) there are in 2.50 g of substance. For this, we divide the mass into the molecular weight Mw) of CH₄:

Mw(CH₄) = 12 g/mol C + (1 g/mol H x 4) = 16 g/mol

moles CH₄ = mass CH₄/Mw(CH₄)= 2.50 g/(16 g/mol) = 0.15625 mol CH₄

Now, we divide the heat released into the moles of CH₄ to obtain the enthalpy per mole of CH₄:

ΔHc = heat/mol CH₄ = 125 kJ/(0.15625 mol) = 800 kJ/mol

Therefore, the enthalpy of combustion of methane is -800 kJ/mol (the minus sign indicated that the heat is released).

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2 years ago

The first eighteen chemical elements on the periodic table are described below in a series of statements. The first 1S letters o

Aleonysh [2.5K]

Answer: The questions looks unclear

Explanation: Periodic table is a table that contains elements arranged according to their increasing atomic number.

1. D belongs to group 4

E. Belongs to group 7

B belongs to group 1

A belongs to group 8. A noble gas.

R belongs to group 3. K belongs to group 6 C belongs to group 1. H belongs to group 8

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2 years ago

When 4.41g of phosphoric acid (H3PO4) react with 9.25g of barium hydroxide, water and insoluble barium phosphate form. [T/I-7] a

AnnZ [28]

Answer:

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

Explanation:

Let's consider the unbalanced equation that occurs when phosphoric acid reacts with barium hydroxide to form water and barium phosphate. This is a neutralization reaction.

H₃PO₄(aq) + Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

We will balance it using the trial and error method.

First, we will balance Ba atoms by multiplying Ba(OH)₂ by 3 and P atoms by multiplying H₃PO₄ by 2.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + H₂O(l)

Finally, we will get the balanced equation by multiplying H₂O by 6.

2 H₃PO₄(aq) + 3 Ba(OH)₂(aq) ⇒ Ba₃(PO₄)₂(s) + 6 H₂O(l)

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2 years ago

Which statement is true of a reversible reaction at equilibrium?

Vedmedyk [2.9K]

Answer:

The concentration of reactants and the concentration of products are constant.

Explanation:

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7 0

2 years ago

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