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1 year ago

If 110. grams of potassium carbonate (K2CO3) is dissolved into 300. mL of solution, what is the molarity of the solution?

Chemistry

2 answers:

Ivan1 year ago

7 0

Answer:

2.7 M

Explanation:

M=moles of solute/volume of solution (L)

First, you need to calculate the number of moles using the given mass and the molar mass.

110 g138.205 g/mol=0.80 mol

Then, you can solve for molarity using the molarity equation.

M=0.80 mol0.300 L=2.7 M

Remember, you need to convert mL to L before you can calculate molarity.

il63 [147K]1 year ago

6 0

Answer:

2.65 M

Explanation:

Convert grams of K₂CO₃ to moles. The molar mass is 138.205 g/mol.

(110 g)/(138.205 g/mol) = 0.796 mol

Convert milliliters of solution to liters.

300 mL = 0.300 L

Divide moles of K₂CO₃ by liters of solution.

0.796 mol/0.300 L = 2.65 mol/L = 0.265 M

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Answer:

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Explanation:

First, we must put down the equation of reaction because it must guide our work.

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2 moles of iron III nitrate yields 1 mole of iron III carbonate

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Theoretical mass yield of iron III carbonate = 3.56×10^-3 moles ×291.73 g∙mol–1 = 1.04g of iron III carbonate

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