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kompoz [17]
2 years ago
15

In the reaction of nitrogen gas with oxygen gas to produce nitrogen oxide, what is the effect of adding more oxygen gas to the i

nitial reaction mixture? the reaction is shown below. n2(g) + o2(g) ⇌ 2no(g)
Chemistry
1 answer:
Alborosie2 years ago
3 0
<h3>Answer:</h3>

The Equilibrium would shift to produce more NO

<h3>Explanation:</h3>

The reaction is;

N₂(g) + O₂(g) ⇆ 2NO(g)

  • When a reaction is at equilibrium then the forward reaction rate will be equivalent to the reverse reaction rate. Additionally, the concentration of the reactants and products are the same.
  • From Le Chatelier's principle, additional reactants favor the formation of more products while additional products favor the formation of more reactants.
  • For example, when more oxygen is added then more Nitrogen (II) oxide will be formed.
  • Oxygen is a reactant and when increased it favors forward reaction which leads to the formation of more NO which is the product.

You might be interested in
How many functional groups does the isopropanol contain that can experience this type of interaction
nalin [4]

Answer:

This question is incomplete

Explanation:

This question is incomplete but what you should know is that isopropanol (also referred to rubbing alcohol) has just one functional group. This functional group is called the hydroxyl group (-OH) and it's the reason the compound name ends with "ol". The hydroxyl group can be seen in the structure of the compound (Isopropanol) below

    H  OH  H

     |     |     |

H- C - C - C - H

     |     |     |

    H   H   H

If there is any functional group in isopropanol required for any form of interaction, that functional group will be the hydroxyl group because that's the only functional group isopropanol has.

NOTE: Functional group is an atom or group of atoms that determines the chemical properties of a compound.

3 0
2 years ago
Calculate the molarity of each solution.
weeeeeb [17]
Q1)
molarity is defined as the number of moles of solute in 1 L solution 
the number of moles of LiNO₃ - 0.38 mol
volume of solution - 6.14 L
since molarity is number of moles in 1 L 
number of moles in 6.14 L - 0.38 mol
therefore number of moles in 1 L - 0.38 mol / 6.14 L = 0.0619 mol/L
molarity of solution is 0.0619 M

Q2)
the mass of C₂H₆O in the solution is 72.8 g
molar mass of C₂H₆O is 46 g/mol 
number of moles = mass present / molar mass of compound
the number of moles of C₂H₆O - 72.8 g / 46 g/mol 
number of C₂H₆O moles - 1.58 mol
volume of solution - 2.34 L
number of moles in 2.34 L - 1.58 mol
therefore number of moles in 1 L - 1.58 mol / 2.34 L = 0.675 M
molarity of C₂H₆O is 0.675 M

Q3)

Mass of KI in solution - 12.87 x 10⁻³ g
molar mass - 166 g/mol
number of mole of KI = mass present / molar mass of KI
number of KI moles = 12.87 x 10⁻³ g / 166 g/mol = 0.0775 x 10⁻³ mol
volume of solution - 112.4 mL 
number of moles of KI in 112.4 mL - 0.0775 x 10⁻³ mol
therefore number of moles in 1000 mL- 0.0775 x 10⁻³ mol / 112.4 mL x 1000 mL
molarity of KI - 6.90 x 10⁻⁴ M
8 0
1 year ago
Which of the following describes a scenario in which the molecular geometry would have the smallest bond angle(s)? (A) four bond
maw [93]

Answer: The correct answer is "B" two bonding domains(or bonding pairs) or two non bonding domains(or lone pairs)

Explanation:

Molecular geometry/structure is a three dimensional shape of a molecule. It is basically an arrangement of atoms in a molecule.It is determined by the central atom, its surrounding atoms and electron pairs.According to VSEPR theory, there are 5 basic shapes of a molecule: linear, trigonal planar, tetrahedral, trigonal bipyramidal and octahedral.

A)Four bonding domains and zero non bonding domains: shape is tetrahedral and bond angle is 109.5°

B)Two bonding domains and two non bonding domains(lone pairs): shape is bent and bond angle is 104.5°

C)Three bonding domains and one non bonding domain: shape is trigonal pyramidal and bond angle is 107°

D)Two bonding domain and zero non bonding domain: shape is linear and bond angle is 107°

E)Two bonding domain and one non bonding domain: bent shape and bond angle is 120°

F)Three bonding domains and zero nonbonding domain: shape is trigonal planar and bond angle is 120°

Hence Two bonding domains and two non bonding domains have the smallest bond angle.

6 0
1 year ago
When HCl(g) reacts with NH3(g) to form NH4Cl(s) , 176 kJ of energy are evolved for each mole of HCl(g) that reacts. Write a bala
Orlov [11]

Answer:

q = -176kJ

Explanation:

HCl and NH3 reacts as following to NH4Cl

HCl(g) + NH3(g)=========>NH4Cl(s)   : ΔH = -176 KJ

Clearly,

ENERGY IS EVOLVED MEANING IT IS A EXOTHERMIC REACTION .

therefore, the value of heat evolved as q = -176kJ

8 0
1 year ago
An equimolar mixture of N2(g) and Ar(g) is kept inside a rigid container at a constant temperature of 300 K. The initial partial
andrey2020 [161]

Answer:

The final pressure of the gas mixture after the addition of the Ar gas is P₂= 2.25 atm

Explanation:

Using the ideal gas law

PV=nRT

if the Volume V = constant (rigid container) and assuming that the Ar added is at the same temperature as the gases that were in the container before the addition, the only way to increase P is by the number of moles n . Therefore

Inicial state ) P₁V=n₁RT

Final state )  P₂V=n₂RT

dividing both equations

P₂/P₁ = n₂/n₁ → P₂= P₁ * n₂/n₁

now we have to determine P₁ and n₂ /n₁.

For P₁ , we use the Dalton`s law , where p ar1 is the partial pressure of the argon initially and x ar1 is the initial molar fraction of argon (=0.5 since is equimolar mixture of 2 components)

p ar₁ = P₁ * x ar₁  →  P₁ = p ar₁ / x ar₁ = 0.75 atm / 0.5 = 1.5 atm

n₁ = n ar₁ + n N₁ =  n ar₁ + n ar₁ = 2 n ar₁

n₂ = n ar₂ + n N₂ = 2 n ar₁ + n ar₁ = 3 n ar₁

n₂ /n₁ = 3/2

therefore

P₂= P₁ * n₂/n₁ = 1.5 atm * 3/2  = 2.25 atm

P₂= 2.25 atm

8 0
2 years ago
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