Answer: d. More than 6.5 grams of copper (II) is formed, and some copper chloride is left in the reaction mixture.
Explanation: 
As can be seen from the chemical equation, 2 moles of aluminium react with 3 moles of copper chloride.
According to mole concept, 1 mole of every substance weighs equal to its molar mass.
Aluminium is the limiting reagent as it limits the formation of product and copper chloride is the excess reagent as (14-7.5)=6.5 g is left as such.
Thus 54 g of of aluminium react with 270 g of copper chloride.
1.50 g of aluminium react with=
of copper chloride.
3 moles of copper chloride gives 3 moles of copper.
7.5 g of copper chloride gives 7.5 g of copper.
Answer:
- <u>259,000 g of chalk.</u>
Explanation:
<u>1) Data:</u>
a) 2000 boxes
b) 175 g / box
c) % yield = 74%
<u>2) Formula: </u>
- % yield = (theoretical yield / actual yield) × 100
<u>3) Solution:</u>
a) Calcualte the actual yield:
- mass of product = 2000 box × 175 g/ box = 350,000 g
b) Solve for the theoretical yield from the % yield formula:
- % yield = (theoretical yield / actual yield) × 100
⇒ theoretical yield = % yield × actual yield / 100
theoretical yield = 74% × 350,000g / 100 = 259,000 g
<span>It's volume is 0.48 cm3Specific </span>
<span>(A)hydrochloric acid + silver nitrate
HCl(aq) + AgNO3(aq) -----> AgCl(s) +HNO3(aq)
</span><span>(B)hydrochloric acid + sodium hydroxide
</span><span>HCl(aq) + NaOH(aq) -----> NaCl(aq) + H2O(l)
</span><span>(C)calcium chloride + silver nitrate
CaCl2(aq) + AgNO3(aq) ----> </span>AgCl(s) +Ca(NO3)2(aq)
<span>(D)sodium chloride + silver nitrate
</span>NaCl(aq) + AgNO3(aq) ----> AgCl(s) +NaNO32(aq)
AgCl is a white precipitate.
In (B) no precipitate was formed, so answer is B.
<span>1.05 g/ml * 1000 ml = 1050g/l because of 1g/ml = 1 kg/l
so, a/q
mass of 4.7 l of whole blood in pound =
4.7 * 1050 = 4935 g
so in pound
4935g = 10.87981p</span>
